Python 3程序中的Elif語法錯誤

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我的代碼的elif語句中出現無效的sytnax錯誤。我究竟做錯了什麼？Python 3程序中的Elif語法錯誤

# define the functions for each math operation 
# 
def add (a, b) : 

    return a + b 

def subtract (a, b) : 

    return a - b 

def multiply (a, b) : 

    return a * b 

def divide (a, b) : 

    return a/b 

def remainder (a, b) : 

    return a % b 

def welcome_message (first_name) : 
    print ("Hi ", first_name, " " ". Welcome to Project 3!") 

welcome_message("Prof. Shah") 

loop = 1 

while loop ==1: 
    print ("Select operation.") 
    print ("1. Add") 
    print ("2. Subtract") 
    print ("3. Multiply") 
    print ("4. Divide") 
    print ("5. Remainder") 
    choice = input("Enter choice :") 
    num1 = int(input |"Please enter your first number: ") 
    num2 = int(input |"Please enter your second number: ") 

    if choice == '1' : 
       print(num1, "+", num2, "=", add (num1,num2) 
     elif choice == '2' : 
       print(num1, "-", num2, "=", subtract (num1,num2) 
     elif choice == '3' : 
       print(num1, "*", num2, "=", multiply (num1,num2) 
     elif choice == '4' : 
       print(num1, "/", num2, "=", divide (num1,num2) 
     elif choice == '5' : 
       print(num1, "%", num2, "=", remainder (num1,num2)

來源

2014-12-07 CherylR

你知道你可以['從運營商導入添加，子，div，mul，mod']（https://docs.python.org/3/library/operator.html），對吧？ – jonrsharpe 2014-12-07 20:34:44

我對Python相當陌生，所以我仍然是一個正在進行的工作！ LOL – CherylR 2014-12-07 20:59:21

if choice == '1' : 
    print(num1, "+", num2, "=", add(num1,num2)) 
elif choice == '2' : 
    print(num1, "-", num2, "=", subtract(num1,num2)) 
...

您的縮進，似乎被關閉了，你人失蹤在每個print語句結束一個右括號。

來源

2014-12-07 20:34:04

Got it！謝謝Haleemur。現在，當我嘗試運行該程序時，出現以下錯誤：Traceback（最近調用最後一次）：文件「/ Users/cherylragin/Desktop/Intro to Interactive Design/Week 4 Assignments/Project3_copy_3_yes.py」，第38行， num1 = int（輸入|「請輸入您的第一個數字：」） TypeError：不受支持的操作數類型爲|：'builtin_function_or_method'和'str' – CherylR 2014-12-07 20:55:02

問題在於以下兩行：'num1 = int（輸入|「請輸入您的第一個數字：」）'和'num2 = int（輸入|「請輸入您的第二個數字：」）'。試着自己解決它，不應該太難，如果你不能，請在你的嘗試後在SO上發帖。祝你好運！ – 2014-12-07 21:04:09

是的......我明白了：我進入了|錯誤中的符號。當我做出更正時，程序運行了，但是我無法計算它。 – CherylR 2014-12-07 21:10:49

if choice == '1' : 
       print(num1, "+", num2, "=", add (num1,num2) 
     elif choice == '2' : 
       print(num1, "-", num2, "=", subtract (num1,num2) 
     elif choice == '3' : 
       print(num1, "*", num2, "=", multiply (num1,num2) 
     elif choice == '4' : 
       print(num1, "/", num2, "=", divide (num1,num2) 
     elif choice == '5' : 
       print(num1, "%", num2, "=", remainder (num1,num2)

問題在這裏。如果「if」塊將要處理，那麼你必須先從if開始，然後elif。像：

if choice == '1' : 
       print(num1, "+", num2, "=", add (num1,num2) 
elif choice == '2' : 
       print(num1, "-", num2, "=", subtract (num1,num2) 
elif choice == '3' : 
       print(num1, "*", num2, "=", multiply (num1,num2) 
elif choice == '4' : 
       print(num1, "/", num2, "=", divide (num1,num2) 
elif choice == '5' : 
       print(num1, "%", num2, "=", remainder (num1,num2)

來源

2014-12-07 20:34:34 GLHF

Python 3程序中的Elif語法錯誤

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