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在我的代碼中，我有一個名爲「ToDoItem」的對象， 而我有另一個名爲「ToDoList」的對象。 應該有一個'ToDoItem'對象的數組。對象列表受到某些別名損壞
編輯 - 一個改變運行能夠代碼：
function ToDoItem(Text, date, isDone = false)
{
\t if (!(typeof(Text) == "string") || (Text.localeCompare("") == 0))
\t {
\t \t return undefined;
\t }
\t if(!(date instanceof Date))
\t \t return("please enter A valid Date");
\t
\t date.setUTCMonth(date.getUTCMonth()-1)
\t console.log(date.getUTCMonth());
\t this.Text = Text; \t \t \t //type of String
\t this.date = date; \t \t \t //type of Date
\t this.isDone = isDone; \t \t //type of boolean
\t
\t if(typeof this.postpone != "function")
\t {
\t \t ToDoItem.prototype.toString = function()
\t \t {
\t \t \t if (typeof(this) == "undefined")
\t \t \t {
\t \t \t alert("here");
\t \t \t \t return;
\t \t \t }
\t \t \t return ("Task: " + this.Text + ", Date:" + this.date + " , isDone: " + this.isDone);
\t \t }
\t \t
\t \t ToDoItem.prototype.isOutOfDate = function(now)
\t \t {
\t \t \t if(now == undefined || !(now instanceof Date))
\t \t \t \t \t return "please enter Date";
\t \t \t \t
\t \t \t if(now < this.date) \t \t \t
\t \t \t \t return true;
\t \t \t return false;
\t \t }
\t \t ToDoItem.prototype.postpone = function(days)
\t \t {
\t \t \t if(days == undefined || !(typeof(days) == "number"))
\t \t \t \t return "please enter a number";
\t \t \t if(days < 0)
\t \t \t \t return "this is negative number";
\t \t \t if(days >= 0)
\t \t \t {
\t \t \t \t var oldDay = this.date.getDate();
\t \t \t \t this.date.setDate(oldDay + days);
\t \t \t }
\t \t } \t
\t }
}
\t
\t
\t
\t
\t
function ToDoList()
{
\t var List =new Array;
\t this.List = List;
\t if(typeof this.addItem != "function")
\t {
\t \t ToDoList.prototype.constructor = ToDoList;
\t \t ToDoList.prototype.toString = function()
\t \t {
\t \t \t var str = "";
\t \t \t for(var i=0;i<List.length;i++)
\t \t \t \t str += i+1 + ":" + List[i].toString() + "\n"; \t \t \t
\t \t \t return str;
\t \t }
\t \t
\t \t ToDoList.prototype.addItem = function(item)
\t \t {
\t \t \t if(item == undefined || (!(item instanceof ToDoItem)))
\t \t \t \t return "please enter object type of item";
\t \t \t
\t \t \t this.List[List.length] = item;
\t \t }
\t \t
\t \t ToDoList.prototype.getForDate = function(date)
\t \t {
\t \t \t if(date == undefined || !(date instanceof Date))
\t \t \t \t return "please enter Date";
\t \t \t
\t \t \t var arr = [];
\t \t \t var capacity = 0;
\t \t \t
\t \t \t for(var i=0;i<List.length;i++)
\t \t \t \t if((List[i].date.getDate() == date.getDate()) && (List[i].date.getMonth() == date.getMonth()) && (List[i].date.getYear() == date.getYear()))
\t \t \t \t \t arr[capacity++] = List[i];
\t \t \t \t
\t \t \t
\t \t \t return arr;
\t \t }
\t \t
\t \t ToDoList.prototype.getOutOfDate = function()
\t \t {
\t \t \t var arr = [];
\t \t \t var capacity = 0;
\t \t \t for(var i=0;i<List.length;i++)
\t \t \t \t if(List[i].isOutOfDate(new Date()) == true)
\t \t \t \t \t arr[capacity++] = item;
\t \t \t return arr;
\t \t }
\t \t
\t \t ToDoList.prototype.postpone = function(index, days)
\t \t {
\t \t \t if(index == undefined || days == undefined || typeof(index) != Number || typeof(days) != Number)
\t \t \t \t return "enter Numbers";
\t \t \t if(days < 0 || index < 0)
\t \t \t \t return "enter valid numbers"; \t \t
\t \t \t if(index >= this.List.length)
\t \t \t \t return "enter valid index"; \t \t \t
\t \t \t
\t \t \t List[i].postpone(days);
\t \t }
\t }
}
function tester()
{
\t var d1 = new Date(2015, 1, 1);
\t var d2 = new Date(2015, 12, 1);
\t var d3 = new Date(2016, 10, 17);
\t var d4 = new Date(2016, 2, 14);
\t var t1 = new ToDoItem("clean the house", d1);
\t var t2 = new ToDoItem("fix toilet", d2);
\t var t3 = new ToDoItem("buy shampoo", d3);
\t var t4 = new ToDoItem("call dad", d4);
\t var l1 = new ToDoList();
\t l1.addItem(t1);
\t l1.addItem(t2);
\t console.log(l1.toString());
\t var l2 = new ToDoList();
\t l2.addItem(t3);
\t l2.addItem(t4);
\t console.log(l2.toString());
}<!DOCTYPE html>
<html>
\t <script type = "text/javascript" src="ToDo.js">
\t </script>
<head>
</head>
<body>
<script>tester();</script>
</body>
</html>問題是，當我生成兩個不同的'ToDoList'對象並打印時，我在第二個對象上得到第一個數據，依此類推。
感謝您的任何幫助。
歡迎的StackOverflow！我查看了你的代碼，但是其中的一些內容從這個問題中漏掉了，特別是'ToDoItem'的代碼。您可以使用代碼片段功能將代碼轉換爲可運行的示例，幷包含使其運行所需的所有代碼？如果編輯問題並使用'<>'按鈕，它會在問題中插入一個可運行的片段。 –
感謝您的評論。 –