Oracle SQL - 組和細節記錄

Question

我正在嘗試構建一個Oracle SQL查詢，當計數大於1時，這會使我按行組織的行與組成的行一起分組。示例和執行分組的SQL查詢。任何幫助或建議將不勝感激。

例如使用下面的數據集 -

====================== 
ID | NAME | AUTHOR 
====================== 
2 | Abc | John 
6 | Abc | John 
3 | Xyz | Mike 
4 | Abc | Mike 
5 | Xyz | John 
1 | Abc | Mike 
7 | PQR | Raj 


Expected Result - 
=========================== 
ID | NAME | AUTHOR | COUNT 
=========================== 
    | Abc |  | 4 
2 | Abc | John |  
6 | Abc | John |  
4 | Abc | Mike |  
1 | Abc | Mike |  
    | PQR |  | 1 
    | Xyz |  | 2 
3 | Xyz | Mike |  
5 | Xyz | John |  


SELECT NAME, COUNT(NAME) from (
SELECT 2 as ID, ' Abc ' as NAME, ' John ' as AUTHOR FROM DUAL 
UNION 
SELECT 6 as ID, ' Abc ' as NAME, ' John ' as AUTHOR FROM DUAL 
UNION 
SELECT 3 as ID, ' Xyz ' as NAME, ' Mike ' as AUTHOR FROM DUAL 
UNION 
SELECT 4 as ID, ' Abc ' as NAME, ' Mike ' as AUTHOR FROM DUAL 
UNION 
SELECT 5 as ID, ' Xyz ' as NAME, ' John ' as AUTHOR FROM DUAL 
UNION 
SELECT 1 as ID, ' Abc ' as NAME, ' Mike ' as AUTHOR FROM DUAL 
UNION 
SELECT 7 as ID, ' PQR ' as NAME, ' Raj ' as AUTHOR FROM DUAL) 
GROUP BY NAME 
ORDER by NAME; 

Answer 1

SQL> with t as (
    2 SELECT 2 as ID, ' Abc ' as NAME, ' John ' as AUTHOR FROM DUAL 
    3 UNION 
    4 SELECT 6 as ID, ' Abc ' as NAME, ' John ' as AUTHOR FROM DUAL 
    5 UNION 
    6 SELECT 3 as ID, ' Xyz ' as NAME, ' Mike ' as AUTHOR FROM DUAL 
    7 UNION 
    8 SELECT 4 as ID, ' Abc ' as NAME, ' Mike ' as AUTHOR FROM DUAL 
    9 UNION 
10 SELECT 5 as ID, ' Xyz ' as NAME, ' John ' as AUTHOR FROM DUAL 
11 UNION 
12 SELECT 1 as ID, ' Abc ' as NAME, ' Mike ' as AUTHOR FROM DUAL 
13 UNION 
14 SELECT 7 as ID, ' PQR ' as NAME, ' Raj ' as AUTHOR FROM DUAL) 
15 select id, name, author, count# 
16 from (
17 select t.id, t.name, t.author, decode(grouping(id),1,count(*),null) count#, 
18 count(*) over (partition by name) cn, grouping(id) gid 
19 from t 
20 group by grouping sets((id,name,author),(name)) 
21 ) 
22 where (cn != 2 or count# is not null) 
23 order by name, gid desc, author 
24/

     ID NAME AUTHOR  COUNT#            
---------- ------ ------ ----------            
      Abc     4            
     2 Abc John               
     6 Abc John               
     4 Abc Mike               
     1 Abc Mike               
      PQR     1            
      Xyz     2            
     5 Xyz John               
     3 Xyz Mike     

Answer 2

select 
    id, name, author, decode(grouping_id(id, name), 2, count(*)) count 
from 
    books 
group by 
    rollup(name, (author, id)) 
having 
    grouping_id(id, name) != 3 
order 
    by name, id nulls first 

Answer 3

的名字與作者的計數分組的數據：

SELECT NULL id, name, NULL author, count(author) "count" 
FROM myTable 
GROUP BY name 

加時，有更多的則是細節一位作者：

SELECT id, name, author, NULL "count" 
FROM mytable 
WHERE name NOT IN (SELECT name FROM myTable GROUP BY name HAVING count(1) = 1) 

少許爲了得到想要的結果

SELECT id, name, author, NULL "count" 
FROM mytable 
WHERE name NOT IN (SELECT name FROM myTable GROUP BY name HAVING count(1) = 1) 
UNION ALL 
SELECT NULL id, name, NULL author, count(author) "count" 
FROM myTable 
GROUP BY name 
ORDER BY 2, 4, 1, 3