PlayFramework 2.2 scala關閉WebSocket連接

Question

如何關閉WebSocket連接？如果您想立即關閉它，documentation上的示例有效。

但是如何處理以下情況：我想在將來發生某種情況時關閉連接。例如，當我收到來自客戶的特定消息時。

def indexWS = WebSocket.using[String] { 
    request => { 

     var channel: Option[Concurrent.Channel[String]] = None 
     var outEnumerator: Enumerator[String] = Concurrent.unicast(c => channel = Some(c)) 

     val myIteratee: Iteratee[String, Unit] = Iteratee.foreach[String] {gotString => { 
     // received a string from the client 

     if (gotString == "close_me") { 
      // outEnumerator = Enumerator.eof // doesn't work 
      // outEnumerator >>> Enumerator.eof // doesn't work 
     } 

     }} 

     (myIteratee, outEnumerator) 
    } 
    } 

謝謝你的幫忙！

Answer 1

我知道了：我不得不去通過我在

var outEnumerator: Enumerator[String] = Concurrent.unicast(c => channel = Some(c)) 

，打開了通道的註釋塊將成爲

if (gotString == "close_me") { 
    channel.foreach(_.eofAndEnd())  
} 

將通過枚舉和關閉推送EOF連接。