2017-10-08 56 views
-1

當我輸入36011時,第二個輸出的結果是36011而不是11,我確信編譯器設置是正確設置的。我真的不知道還有什麼要做,我必須使用long long long來完成這個任務,並且當我嘗試在我的代碼中使用mod函數時,它不適用於我。MOD功能對我來說無法正常工作

#include <iostream> 

using namespace std; 

int main() 
{ 
long long int seconds; 

cin >> seconds; 

long long int minutes = seconds/60; 
long long int hours = minutes/60; 
long long int days = hours/24; 

cout << "Total seconds: " << seconds << endl; 

if(seconds <= 0) 
{ 
    cout << "\nTotal seconds must be greater than zero"; 
} 

else 
{ 
    if(days > 0) 
    { 
     hours %= 24; 
     cout << "\n" << days << " day(s)"; 
    } 
    if(hours > 0) 
    { 
     minutes %= 60; 
     cout << "\n" << hours << " hour(s)"; 
    } 
    if(minutes > 0) 
    { 
     seconds %= 60; 
     cout << "\n" << minutes << " minute(s)"; 
    } 
    if(seconds > 0) 
    { 
     cout << "\n" << seconds << " second(s)"; 
    } 
} 
cout << endl; 

return 0;} 
+1

當你輸入'36011'作爲'秒',''分鐘'變量將保存'600'。因此,當「分鐘%= 60」時,「分鐘」將保持爲「0」。正因爲如此,你的'if(minutes> 0){...}'不會被執行,並且不會在'seconds'上執行模運算符。使用調試器非常容易找到,我強烈建議您學習如何操作 – Fureeish

回答

0

您正在計算您的值錯誤的方式。試試更像這樣的代碼:

#include <iostream> 

using namespace std; 

int main() 
{ 
    long long int seconds; 
    cin >> seconds; 

    if (seconds <= 0) 
    { 
     cout << "Total seconds must be greater than zero" << endl; 
    } 
    else 
    { 
     cout << "Total seconds: " << seconds << endl; 

     long long int minutes = seconds/60; seconds %= 60; 
     long long int hours = minutes/60; minutes %= 60; 
     long long int days = hours/24; hours %= 24; 

     /* alternatively: 
     long long int days = seconds/86400; seconds %= 86400; 
     long long int hours = seconds/3600; seconds %= 3600; 
     long long int minutes = seconds/60; seconds %= 60; 
     */ 

     if (days > 0) { 
      cout << days << " day(s)" << endl; 
     } 
     if (hours > 0) { 
      cout << hours << " hour(s)" << endl; 
     } 
     if (minutes > 0) { 
      cout << minutes << " minute(s)" << endl; 
     } 
     if (seconds > 0) { 
      cout << seconds << " second(s)" << endl; 
     } 
    } 

    return 0; 
}