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我在測驗應用程序上顯示正確分數時遇到問題 - 特別是與複選框。我有四個選擇,但只有兩個是正確的(B & C)。當選擇了所有四個選項(不正確)時,它仍然會添加這些點。如何防止這種情況發生並正確得分這些複選框?有人知道嗎?謝謝!使用CheckBox計算簡單問答應用程序的正確分數
package com.example.android.quantummechanicsquiz;
import android.provider.MediaStore;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.text.Editable;
import android.view.View;
import android.widget.CheckBox;
import android.widget.EditText;
import android.widget.RadioButton;
import android.widget.TextView;
import android.widget.Toast;
public class MainActivity extends AppCompatActivity {
int score = 0;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
}
public void radioButtonClicked(View view) {
boolean checked = ((RadioButton) view).isChecked();
switch (view.getId()) {
case R.id.radio_one_correct:
if (checked) break;
case R.id.radio_one_b:
if (checked) break;
case R.id.radio_one_c:
if (checked) break;
case R.id.radio_one_d:
if (checked) break;
case R.id.radio_two_a:
if (checked) break;
case R.id.radio_two_b:
if (checked) break;
case R.id.radio_two_correct:
if (checked) break;
case R.id.radio_two_d:
if (checked) break;
case R.id.radio_four_a:
if (checked) break;
case R.id.radio_four_b:
if (checked) break;
case R.id.radio_four_correct:
if (checked) break;
case R.id.radio_four_d:
if (checked) break;
case R.id.radio_five_a:
if (checked) break;
case R.id.radio_five_b:
if (checked) break;
case R.id.radio_five_c:
if (checked) break;
case R.id.radio_five_correct:
if (checked) break;
}
}
private int calculateScore(boolean answerOne, boolean answerTwo, boolean answerThreeA,
boolean answerThreeB, boolean answerThreeC, boolean answerThreeD,
boolean answerFour, boolean answerFive, Editable answerSix) {
score = 100;
if (answerOne) {
} else {
score = score - 100/6;
}
if (answerTwo) {
} else {
score = score - 100/6;
}
if (answerThreeB && answerThreeC) {
} else {
score = score - 100/6;
}
if (answerFour) {
} else {
score = score - 100/6;
}
if (answerFive) {
} else {
score = score - 100/6;
}
if (answerSix.toString().equals("")) {
score = score - 100/6;
} else {
}
return score;
}
public void submitScore(View view) {
RadioButton answerOne = (RadioButton) findViewById(R.id.radio_one_correct);
boolean correctAnswerOne = answerOne.isChecked();
RadioButton answerTwo = (RadioButton) findViewById(R.id.radio_two_correct);
boolean correctAnswerTwo = answerTwo.isChecked();
CheckBox answerThreeA = (CheckBox) findViewById(R.id.checkbox_three_a);
boolean incorrectAnswerThreeA = answerThreeA.isChecked();
CheckBox answerThreeB = (CheckBox) findViewById(R.id.checkbox_three_b_correct);
boolean correctAnswerThreeB = answerThreeB.isChecked();
CheckBox answerThreeC = (CheckBox) findViewById(R.id.checkbox_three_c_correct);
boolean correctAnswerThreeC = answerThreeC.isChecked();
CheckBox answerThreeD = (CheckBox) findViewById(R.id.checkbox_three_d);
boolean incorrectAnswerThreeD = answerThreeD.isChecked();
RadioButton answerFour = (RadioButton) findViewById(R.id.radio_four_correct);
boolean correctAnswerFour = answerFour.isChecked();
RadioButton answerFive = (RadioButton) findViewById(R.id.radio_five_correct);
boolean correctAnswerFive = answerFive.isChecked();
EditText answerSix = (EditText) findViewById(R.id.question_six_edit_text);
Editable correctAnswerSix = answerSix.getEditableText();
int finalScore = calculateScore(correctAnswerOne, correctAnswerTwo,
incorrectAnswerThreeA, correctAnswerThreeB, correctAnswerThreeC,
incorrectAnswerThreeD, correctAnswerFour, correctAnswerFive, correctAnswerSix);
Toast.makeText(this, "Congratulations! You have a score of " + finalScore + " out of " +
"100", Toast.LENGTH_LONG).show();
}
}
你需要所有這些都在'if else'中。否則,如果這是真的,它仍然會擊中「B && C」。而你真正需要的只是一個'if'來檢查那些不正確的。我認爲。但是你的代碼對你如何處理它很困惑。 – codeMagic
如果還有什麼需要的話? – Mir