如何用鼠標移動圖片？ C＃形式

Question

我想用我的鼠標，所以我就到這裏來移動一個PictureBox：

private void pictureB_Paint(object sender, PaintEventArgs e) 
    { 
     e.Graphics.DrawImage(image, recLoc); 
    } 
    private void pictureB_MouseDown(object sender, MouseEventArgs e) 
    { 
     WorkAble = true; 
     choosingPoint.X = e.X; 
     choosingPoint.Y = e.Y; 
     lastPoint.X = e.X; 
     lastPoint.Y = e.Y; 
    } 

    private void pictureB_MouseMove(object sender, MouseEventArgs e) 
    { 
     if (WorkAble) 
     { 
      recLoc.X = e.X - choosingPoint.X;// + lastPoint.X; 
      recLoc.Y = e.Y - choosingPoint.Y;// + lastPoint.Y; 
      pictureB.Refresh(); 
     } 
    } 

    private void pictureB_MouseUp(object sender, MouseEventArgs e) 
    { 
     WorkAble = false; 
     lastPoint.X = e.X; 
     lastPoint.Y = e.Y; 
    } 
    // recLoc = pictureBox Location. 

好，它的偉大工程。但是不是完全.. 一旦執行KeyUp事件我的意思是，然後再次單擊該圖像將返回到pictureBox的0,0點。 爲了克服這一點，我添加了lastPoint點，並在鼠標移動中添加它的值。 因此，一方面它確實在最後一個下降的點上繪製圖像，但鼠標將位於圖像的0,0點，而不是我點擊的位置 - 圖像上。就像我點擊圖像的中心，鼠標將在0，0點..

任何建議如何解決它？

Answer 1

請對 「recLoc」 增量變化，以避免失去原來的位置：

private void pictureB_MouseMove(object sender, MouseEventArgs e) 
{ 
    if (WorkAble) 
    { 
     recLoc.X = recLoc.X + e.X - choosingPoint.X; 
     recLoc.Y = recLoc.Y + e.Y - choosingPoint.Y; 
     choosingPoint = e.Location; 
     pictureB.Invalidate(); 
    } 
} 

Answer 2

private void pictureB_MouseDown(object sender, MouseEventArgs e) 
    { 
     WorkAble = true; 
     lastPoint.X = e.X; 
     lastPoint.Y = e.Y; 
    } 

     private void pictureBox_MouseUp(object sender, MouseEventArgs e) 
     { 
      mouseMove = false; 
      lastPointX = e.X; 
      lastPointY = e.Y; 
     } 


private void pictureB_MouseMove(object sender, MouseEventArgs e) 
{ 
    if (WorkAble) 
    { 
     recLoc.X -= (lastPoint.X - e.X); 
     recLoc.Y -= (lastPoint.X - e.X); 
     pictureB.Refresh(); 
     choosingPoint = e.Location; 
    } 
}