加入以下查詢？

Question

我正在執行這兩個查詢。

1.

select widget_uid,param_value as campaign_name 
from widget_config_value 
where widget_uid in (select widget_uid 
        from widget_config_value 
        where param_name="active" 
          and param_value="1" 
          and widget_uid in (select widget_uid 
               from partner_widget 
               where partner_uid=4) 
        ) 
     and param_name="widgetCampaignName"; 

2.

select widget_uid,param_value as campaign_type 
from widget_config_value 
where widget_uid in (select widget_uid 
        from widget_config_value 
        where param_name="active" 
          and param_value="1" 
          and widget_uid in (select widget_uid 
               from partner_widget 
               where partner_uid=4) 
        ) 
     and param_name="widgetType"; 

我怎樣才能將這個上widget_uid？所以，我可以得到常見的widget_uid的結果??

還是有什麼辦法來改善上面的查詢？

Answer 1

，您可以嘗試通過以下方式 -

select widget_uid, campaign_name, campaign_type from 
(select widget_uid,param_value as campaign_name from widget_config_value 
where widget_uid in 
(select widget_uid from widget_config_value 
where param_name="active" 
and param_value="1" 
and widget_uid in (select widget_uid from partner_widget where partner_uid=4)) 
and param_name="widgetCampaignName") tbl1, 
(select widget_uid,param_value as campaign_type 
from widget_config_value 
where widget_uid in 
(select widget_uid 
from widget_config_value 
where param_name="active" 
and param_value="1" 
and widget_uid in (select widget_uid from partner_widget where partner_uid=4)) 
and param_name="widgetType") tbl2 
where tbl1.widget_uid = tbl2.widget_uid; 

Answer 2

我想查詢將不能工作，因爲這是不可能的

param_name="active" and param_name="widgetCampaignName" 

的同時

。也查詢不。 2

看看你的查詢

select 
    widget_uid,param_value as campaign_name 
from widget_config_value 
where 
    widget_uid in (
     select widget_uid 
     from 
      widget_config_value 
     where 
      param_name="active" and 
      param_value="1" and 
      widget_uid in (
       select widget_uid 
       from partner_widget 
       where partner_uid=4) 
      ) and 
    param_name="widgetCampaignName"; 

在這部分

select widget_uid 
     from 
      widget_config_value 
     where 
      param_name="active" and 
      param_value="1" and 
      widget_uid in (
       select widget_uid 
       from partner_widget 
       where partner_uid=4) 
      ) 

給你widget_config_value數據是不可能有param_name not equal to "active"。所以param_name="widgetCampaignName"是沒用的。