您可以通過實現自定義JsonConverter
爲DataSet這樣得到你想要的JSON:
class CustomDataSetConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return (objectType == typeof(DataSet));
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
DataSet x = (DataSet)value;
JObject jObject = new JObject();
DataTable a = x.Tables["A"];
foreach (DataColumn col in a.Columns)
{
jObject.Add(col.Caption.ToLower(), a.Rows[0][col].ToString());
}
JArray jArray = new JArray();
DataTable b = x.Tables["B"];
foreach (DataRow row in b.Rows)
{
JObject jo = new JObject();
foreach (DataColumn col in b.Columns)
{
jo.Add(col.Caption.ToLower(), row[col].ToString());
}
jArray.Add(jo);
}
jObject.Add("details", jArray);
jObject.WriteTo(writer);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
throw new NotImplementedException();
}
}
這裏是一個演示:
class Program
{
static void Main(string[] args)
{
DataSet x = new DataSet();
DataTable a = x.Tables.Add("A");
a.Columns.Add("Type");
a.Columns.Add("Value");
a.Rows.Add("A", "100");
DataTable b = x.Tables.Add("B");
b.Columns.Add("Name");
b.Columns.Add("Age");
b.Columns.Add("Gender");
b.Rows.Add("John", "45", "M");
b.Rows.Add("Sebastian", "34", "M");
b.Rows.Add("Marc", "23", "M");
b.Rows.Add("Natalia", "34", "F");
JsonSerializerSettings settings = new JsonSerializerSettings();
settings.Converters.Add(new CustomDataSetConverter());
settings.Formatting = Formatting.Indented;
string json = JsonConvert.SerializeObject(x, settings);
Console.WriteLine(json);
}
}
輸出:
{
"type": "A",
"value": "100",
"details": [
{
"name": "John",
"age": "45",
"gender": "M"
},
{
"name": "Sebastian",
"age": "34",
"gender": "M"
},
{
"name": "Marc",
"age": "23",
"gender": "M"
},
{
"name": "Natalia",
"age": "34",
"gender": "F"
}
]
}
datatable A和dataset.Tables [1]爲datatable B –