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我有一個應用程序，需要一個攝像頭圖像，並在位圖上放置魚眼失真效果。大約需要20多秒才能應用效果並重新繪製位圖。我決定實現一個處理程序來加速第二個線程中的處理。處理程序代碼似乎對應用程序沒有影響。基本上，當滑動條被用戶移動時，這會使位圖變形得更多。 sldebar移動和重繪（）之間存在顯着的延遲。我是否正確地使用了這個？謝謝馬特。處理程序沒有加速在輔助線程中的應用程序
public class TouchView extends View{
private File tempFile;
private byte[] imageArray;
private Bitmap bgr;
private Bitmap bm;
private Bitmap bgr2 = null;;
private Paint pTouch;
private int centreX = 1;
private int centreY = 1;
private int radius = 50;
private int Progress;
private static final String TAG = "*********TouchView";
private Filters f = null;
private Handler handler = new Handler() {
@Override
public void handleMessage(Message msg) {
super.handleMessage(msg);
}
};
public TouchView(Context context) {
super(context);
// TouchView(context, null);
}
public TouchView(Context context, AttributeSet attr) {
super(context,attr);
//......code that loads bitmap from sdcard
BitmapFactory.Options bfo = new BitmapFactory.Options();
bfo.inSampleSize = 1;
bm = BitmapFactory.decodeByteArray(imageArray, 0, imageArray.length, bfo);
bgr = Bitmap.createBitmap(bm.getWidth(), bm.getHeight(), bm.getConfig());
bgr = bm.copy(bm.getConfig(), true);
bgr2 = Bitmap.createBitmap(bm.getWidth(), bm.getHeight(), bm.getConfig());
f = new Filters();
}// end of touchView constructor
public void findCirclePixels(){
Log.e(TAG, "inside fcp()");
float prog = (float)Progress/150000;
bgr2 = f.barrel(bgr,prog);
}// end of changePixel()
@Override
public boolean onTouchEvent(MotionEvent ev) {
switch (ev.getAction()) {
case MotionEvent.ACTION_DOWN: {
centreX = (int) ev.getX();
centreY = (int) ev.getY();
findCirclePixels();
invalidate();
break;
}
case MotionEvent.ACTION_MOVE: {
centreX = (int) ev.getX();
centreY = (int) ev.getY();
findCirclePixels();
invalidate();
break;
}
case MotionEvent.ACTION_UP:
break;
}
return true;
}//end of onTouchEvent
public void initSlider(final HorizontalSlider slider)
{
Log.e(TAG, "******setting up slider*********** ");
slider.setOnProgressChangeListener(changeListener);
}
private OnProgressChangeListener changeListener = new OnProgressChangeListener() {
@Override
public void onProgressChanged(View v, int progress) {
// TODO Auto-generated method stub
setProgress(progress);
processThread();
Log.e(TAG, "***********progress = "+Progress);
}
};
private void processThread() {
new Thread() {
public void run() {
Log.e(TAG, "about to call findcirclepixel in new thread");
findCirclePixels();
handler.sendEmptyMessage(0);
}
}.start();
}
@Override
public void onDraw(Canvas canvas){
super.onDraw(canvas);
canvas.drawBitmap(bgr2, 0, 0, null);
}//end of onDraw
protected void setProgress(int progress2) {
this.Progress = progress2;
findCirclePixels();
invalidate();
}
}
維亞斯我記得現在閱讀，謝謝。我試過看AsyncTask，但不知道如何將它應用到我的應用程序。我會發表另一個問題。 – turtleboy 2011-06-08 19:13:15