2
我打開元素.popin-foto
popin。當我嘗試在同一元素中打開子類popin時,它不起作用。JavaScript的繼承:如何
代碼
這是父
function Popin(container, titulo, url_listagem) {
this.url_listagem = url_listagem;
this.titulo = titulo;
this.overlay = $(".popin-overlay");
this.closeButton = $(".popin-close");
this.container = container;
}
Popin.prototype.header = function() {
var dados = {titulo: this.titulo};
var html = $.tmpl("header", dados);
this.container.append(html);
};
Popin.prototype.body = function() {
var html = $.tmpl("body");
this.container.append(html);
};
Popin.prototype.footer = function() {
var html = $.tmpl("footer");
this.container.append(html);
};
Popin.prototype.close = function() {
var self = this;
this.container.hide(100,function(){
self.overlay.fadeOut('fast');
});
$(".popin-header").remove();
$(".popin-body").remove();
$(".popin-footer").remove();
};
Popin.prototype.open = function(){
var self = this;
this.header();
this.body();
this.footer();
this.closeButton.click(function(){
self.close();
});
this.overlay.fadeTo("fast", 0.8, function(){
self.container.show();
});
};
子類
function PopinFoto(){}
PopinFoto.prototype = new Popin($(".popin-fotos"), "fotos", "fake_url");
PopinFoto.prototype.open = function(){
Popin.prototype.open.call(this);
$(".enviar-foto").die().live('click', function(){
//do something
});
};
所以,我這樣做:
var popin = new Popin($(".popin-foto"), "title", "link");
popin.open();
popin.close();
var popinFoto = new PopinFoto($(".popin-foto"), "title", "link");
popinFoto.open(); //this not works
popin.close();
而在控制檯中,沒有錯誤發生。
你能幫我嗎?
我試試這個,但沒有工作。當我這樣做時,沒有將PopinFoto設置爲Popin的子類,所以它沒有父類的原型函數,例如this.body。 –