Question

我一直在玩java的硒，我遇到了一個問題，我不知道。 http://www.legalcontracts.com/contracts/lease-agreement-form/?ldcn=menu+name

從第三頁（地址頁）要到第四 我能夠設置地址：

這個頁面在這裏

@FindBy(xpath="//div[@class=' qd spropertyAddress']/div[@class='ans']/input") 
    private WebElement address; 

public void SetAddress(String addressName){ 
     address.sendKeys(addressName); 
    } 

但是當我試圖繼續

@FindBy(xpath="//a[contains(text(),'Continue')]") 
    private WebElement continuebutton; 
continuebutton.click(); 

我收到一個org.openqa.selenium.ElementNotVisibleException。繼續按鈕與前一頁的編號相同，因此我不確定這是否與它有關。我嘗試了很多不同的方法來嘗試處理這個問題，但似乎可行的唯一方法是thread.sleep，這不是一個很好的處理方法。

東西我曾嘗試：

WebDriverWait wait = new WebDriverWait(driver,30); 
     wait.until(ExpectedConditions.elementToBeClickable(continuebutton)); 
     wait.until(ExpectedConditions.elementToBeClickable(continuebutton)); 
     wait.until(ExpectedConditions.presenceOfElementLocated((By) continuebutton)); 
     wait.until(ExpectedConditions.visibilityOfElementLocated((By) continuebutton)); 


public void waitForJQuery(WebDriver driver) { 
    (new WebDriverWait(driver, 10)).until(new ExpectedCondition<Boolean>() { 
     public Boolean apply(WebDriver d) { 
      JavascriptExecutor js = (JavascriptExecutor) d; 
      return (Boolean) js.executeScript("return !!window.jQuery && window.jQuery.active == 0"); 
     } 
    }); 
} 

public void waitForJavaScript(WebDriver driver){ 
    (new WebDriverWait(driver, 10)).until(new ExpectedCondition<Boolean>() { 
     public Boolean apply(WebDriver driver) { 
      return ((JavascriptExecutor)driver).executeScript("return document.readyState").equals("complete"); 
     } 
    } 
); 

public void checkPageIsReady(WebDriver driver) { JavascriptExecutor js = (JavascriptExecutor)driver; //Initially bellow given if condition will check ready state of page. 

    if (js.executeScript("return document.readyState").toString().equals("complete")){ 
     System.out.println("Page Is loaded."); 
     return; 
     } 

    //This loop will rotate for 25 times to check If page Is ready after every 1 second. 
    //You can replace your value with 25 If you wants to Increase or decrease wait time. 
    for (int i=0; i<25; i++){ 
     try { 
      Thread.sleep(1000); } 
     catch (InterruptedException e) {} 

     //To check page ready state. 
     if (js.executeScript("return document.readyState").toString().equals("complete")){ 
      break; } } 
    } 

我進來從以前的頁面相同的繼續進行，但在不同的頁面對象：

@FindBy(xpath="//a[contains(text(),'Continue')]") 
    private WebElement continuebutton; 
continuebutton.click(); 

能硒是混淆了當前繼續按鈕，前一個？

Answer 1

使用下面的代碼：

driver.findElement(By.cssSelector("div.ans>input#ctl00_Content_ctrlQuestions_ctl194_ctl21_ctl06_ctl01_ctl01_ctl01_in")).click(); 

driver.findElement(By.cssSelector("div.ans>input#ctl00_Content_ctrlQuestions_ctl194_ctl21_ctl06_ctl01_ctl01_ctl01_in")).clear(); 

driver.findElement(By.cssSelector("div.ans>input#ctl00_Content_ctrlQuestions_ctl194_ctl21_ctl06_ctl01_ctl01_ctl01_in")).sendKeys("ur address"); 

Thread.sleep(2000); 

//click on continue button 

driver.findElement(By.cssSelector(" .largeProceedButton.continueButtonnContinueFirst.nContinue")).click(); 

，而不是使用XPath的就是我上面提到點擊繼續按鈕cssSelector。