0
在Textbox
和規則所列應停止並等待用戶按Button
信息後,讓他「秀」他讀過的信息...繼續代碼按下按鈕
此代碼後應向前跑,並在下一循環
再次等待(我找了活動等等,但我沒有找到任何解決方案)如果你希望你的程序停止,讓用戶確認
public void Auslesen(object e, EventArgs myevent)
{
StringBuilder strbuildsection = new StringBuilder();
StringBuilder strbuildbetreff = new StringBuilder();
StringBuilder strbuildinhalt = new StringBuilder();
StringBuilder strbuilduser = new StringBuilder(System.Environment.UserName);
StringBuilder strbuildusercheck = new StringBuilder();
foreach (string Ccat in this.ini.IniGetCategories())
{
string readval = ini.IniReadValue(Ccat, "Read");
string usercheckvar = (this.ini.IniReadValue(Ccat, "SpecifyUser"));
string user = System.Environment.UserName;
if (readval == "0")
{
if (usercheckvar == user || usercheckvar.Equals("All"))
{
strbuildsection.Append(Ccat + Environment.NewLine);
foreach (string cat in this.ini.IniGetKeys(Ccat))
{
strbuildinhalt.Clear();
strbuildusercheck.Clear();
strbuildbetreff.Clear();
strbuildbetreff.Append(this.ini.IniReadValue(Ccat, "Betreff") + Environment.NewLine);
strbuildinhalt.Append(this.ini.IniReadValue(Ccat, "Inhalt") + Environment.NewLine);
}
textBox1.AppendText(strbuildsection.ToString() + strbuildbetreff.ToString() + strbuildinhalt.ToString() + strbuildusercheck.ToString() + Environment.NewLine);
strbuildsection.Clear();
//
//
//
}
}
}
}
無論如何,這是某種事件驅動的程序。這些程序不會爲用戶「停止」。相反,他們對用戶做出反應。 –
他們如何與用戶「反應」? – Schrader
當用戶做某事時會觸發事件。應用程序的所有代碼都在事件處理程序中,對事件作出反應。 –