如何找到的第一個字符的SQL Server 2008開始

Question

DECLARE @input NVARCHAR(MAX) = 'Create Procedure Test' 
DECLARE @SearhString NVARCHAR(MAX) = 'Procedure' 

DECLARE @index BIGINT = CHARINDEX(@keyword, @input) 

1 - 我想找到的下一個字符的長度字符串程序後啓動

2 - 從那以後，我要檢查，如果DBO字符串在該長度之後存在於指定的位置。

假設第一個字符測試串程序開始後第14位，所以我必須使用

DECLARE @String varchar(20) = SUBSTRING(@input, 21, 10) 

Declare @StringIndex BIGINT = CHARINDEX('dbo.', @String) 

Declare @FirstCharacterIndex BIGINT(This will be the index of the first character) 

如果@String不包含字符串DBO然後東西MYSCHEMA串測試前。

請建議。

UPDATE

我已經更新我的問題圖22是@index的結果+ @FirstCharacterIndex + 9

@index = 8

@FirstCharacterIndex = 4（3計數空間和第4個爲第一個字符）

9 =字符串的字符數程序

Answer 1

試試下面這個SQL：

DECLARE @input NVARCHAR(MAX) = 'Create Procedure Test'; 
DECLARE @input2 NVARCHAR(MAX) = 'Create Procedure dbo Test'; 
DECLARE @SearchString NVARCHAR(MAX) = 'Procedure'; 

DECLARE @index BIGINT = CHARINDEX(@SearchString, @input); 


select @input, @SearchString as searchstring, @index as Index_SearchString , @index +len(@SearchString) as Last_CharacterOfSearchString 
, charIndex('Test', @input,@index +len(@SearchString)) as test_Index 
, charIndex('dbo', @input,@index +len(@SearchString)) as dbo_Index 
, substring(@input, 0, @index +len(@SearchString)) as str1 
, substring(@input, @index +len(@SearchString), len(@input)-@index +len(@SearchString)) as str2 

Declare @dbo_Index int 
Declare @str1 nvarchar(max), @str2 nvarchar(max) 
set @dbo_Index = charIndex('dbo', @input,@index +len(@SearchString)) 

--select @dbo_Index 
if @dbo_Index = 0 
begin 
    set @str1 = substring(@input, 0, @index +len(@SearchString)) 
    set @str2 = substring(@input, @index +len(@SearchString), len(@input)-@index +len(@SearchString)) 

    select @str1 + ' ' + 'MySchema' + @str2 
end 

--,charIndex('dbo',@input2, @index +len(@SearchString)) as dbo_Index 

更新時間：
目標：獲取

DECLARE @input2 NVARCHAR(MAX) = 'Create Procedure Under Fire Test'; 
DECLARE @SearchString NVARCHAR(MAX) = 'Procedure'; 


--,charIndex('dbo',@input2, @index +len(@SearchString)) as dbo_Index 
select substring(@input2,17,25) 
, CHARINDEX(@SearchString,@input2,0) + len(@SearchString) as LastIndexOf_Procedure 
, CHARINDEX('Test',@input2,0) 
,len(@input2) 
,substring(@input2, CHARINDEX(@SearchString,@input2,0) + len(@SearchString), CHARINDEX('Test',@input2,0)- (CHARINDEX(@SearchString,@input2,0)+len(@SearchString))) 



set @SearchString= Ltrim(rtrim(substring(@input2, CHARINDEX(@SearchString,@input2,0) + len(@SearchString), CHARINDEX('Test',@input2,0)- (CHARINDEX(@SearchString,@input2,0)+len(@SearchString))))) 

select @SearchString 
select 
@input2 
,@SearchString as SearchString 
,CHARINDEX(@SearchString,@input2,0) as FirstCharacterIndex