獲取數SUBSTRING（）的SQL Server 2008 R2

Question

我有一些數據，如下所示：

AS WRITTEN            | UNITS | ROUTINE 
TRANSFUSE - RED BLOOD CELLS 1 UNITS ROUTINE, TRANSF... | 1  | 
TRANSFUSE - RED BLOOD CELLS 2UNITS ROUTINE, TRAN... | 2  | 
TRANSFUSE FRESH FROZEN PLASMA 2 ROUTINE    |  | 2 
TRANSFUSE - RED BLOOD CELLS 2 UNITS ROUTINE, TRAN... | 2  | 
TRANSFUSE CRYOPRECIPITATE 10 ROUTINE     |  | <- 10 SHOULD BE HERE 

我使用以下SELECT語句獲取的值，這可能是粗的方式，但這是我第一次進入SUBSTRING()CHARINDEX等。

SELECT語句：

, CASE 
    WHEN SUBSTRING(SO.DESC_AS_WRITTEN, CHARINDEX('UNIT', SO.DESC_AS_WRITTEN)-2,1) NOT IN (
     '1','2','3','4','5','6','7','8','9','10','11' 
    ) 
     THEN '' 
    ELSE SUBSTRING(SO.DESC_AS_WRITTEN, CHARINDEX('UNIT', SO.DESC_AS_WRITTEN)-2,1) 
    END AS [UNITS] 
, CASE 
    WHEN SUBSTRING(SO.DESC_AS_WRITTEN, CHARINDEX('ROUTINE', SO.DESC_AS_WRITTEN)-2,1) NOT IN (
     '1','2','3','4','5','6','7','8','9','10','11' 
    ) 
     THEN '' 
    ELSE SUBSTRING(SO.DESC_AS_WRITTEN, CHARINDEX('ROUTINE', SO.DESC_AS_WRITTEN)-2,2) 
    END AS [ROUTINE] 

正如上面有10個表示應該顯示ROUTINE下，在最後一列，但不是我不明白爲什麼。所有其他人似乎都工作得很好。

謝謝

UPDATE 從從@EkriirkE和@GoatCO大的幫助，我用下面的代碼的解決方案：

,(CAST 
    (ISNULL 
     (REPLACE 
      (REPLACE 
       (REPLACE 
        (CASE 
         WHEN PATINDEX('%[0-9]UNIT%',so.desc_as_written) > 0 
          THEN SUBSTRING(so.desc_as_written, 
           PATINDEX('%[0-9]UNIT%',so.desc_as_written)-1,2) 
         WHEN PATINDEX('%[0-9] UNIT%',so.desc_as_written) > 0 
          THEN SUBSTRING(so.desc_as_written, 
           PATINDEX('%[0-9] UNIT%',so.desc_as_written)-1,2) 
         WHEN PATINDEX('%[0-9]ROUTINE%',so.desc_as_written) > 0 
          THEN SUBSTRING(so.desc_as_written, 
           PATINDEX('%[0-9]ROUTINE%',so.desc_as_written)-1,2) 
         WHEN PATINDEX('%[0-9] ROUTINE%',so.desc_as_written) > 0 
          THEN SUBSTRING(so.desc_as_written, 
           PATINDEX('%[0-9] ROUTINE%',so.desc_as_written)-1,2) 
         WHEN PATINDEX('%[0-9]STAT%',so.desc_as_written) > 0 
          THEN SUBSTRING(so.desc_as_written, 
           PATINDEX('%[0-9]STAT%',so.desc_as_written)-1,2) 
         WHEN PATINDEX('%[0-9] STAT%',so.desc_as_written) > 0 
          THEN SUBSTRING(so.desc_as_written, 
           PATINDEX('%[0-9] STAT%',so.desc_as_written)-1,2) 
         WHEN PATINDEX('%[0-9]TODAY%',so.desc_as_written) > 0 
          THEN SUBSTRING(so.desc_as_written, 
           PATINDEX('%[0-9]TODAY%',so.desc_as_written)-1,2) 
         WHEN PATINDEX('%[0-9] TODAY%',so.desc_as_written) > 0 
          THEN SUBSTRING(so.desc_as_written, 
           PATINDEX('%[0-9] TODAY%',so.desc_as_written)-1,2) 
        END, 
       'S',''), 
      'T',''), 
     'U','') 
    , 0) 
AS INT) 
) AS [TEST] 

Answer 1

這可能是更好的：

SELECT *,CASE WHEN PATINDEX('%[0-9]UNITS%',written) > 0 THEN SUBSTRING(written,PATINDEX('%[0-9]UNITS%',written)-1,2) 
       WHEN PATINDEX('%[0-9] UNITS%',written) > 0 THEN SUBSTRING(written,PATINDEX('%[0-9] UNITS%',written)-1,2) 
     END 
     ,CASE WHEN PATINDEX('%[0-9]ROUTINE%',written) > 0 THEN SUBSTRING(written,PATINDEX('%[0-9]ROUTINE%',written)-1,2) 
       WHEN PATINDEX('%[0-9] ROUTINE%',written) > 0 THEN SUBSTRING(written,PATINDEX('%[0-9] ROUTINE%',written)-1,2) 
     END 
FROM #Table1 

演示：SQL Fiddle

這可能是最簡單的包裹CASE語句內更換，而不是對付抓住人物給出的變化適當數量的，即：

SELECT *,REPLACE(CASE WHEN PATINDEX('%[0-9]UNITS%',written) > 0 THEN SUBSTRING(written,PATINDEX('%[0-9]UNITS%',written)-1,2) 
         WHEN PATINDEX('%[0-9] UNITS%',written) > 0 THEN SUBSTRING(written,PATINDEX('%[0-9] UNITS%',written)-1,2) 
       END,'S','')      
     ,REPLACE(CASE WHEN PATINDEX('%[0-9]ROUTINE%',written) > 0 THEN SUBSTRING(written,PATINDEX('%[0-9]ROUTINE%',written)-1,2) 
         WHEN PATINDEX('%[0-9] ROUTINE%',written) > 0 THEN SUBSTRING(written,PATINDEX('%[0-9] ROUTINE%',written)-1,2) 
       END,'S','') 
FROM #Table1 

Answer 2

僅拍攝1後盾後焦從查找UNIT或ROUTINE開始查找2個字符。 「10 ROUTINE」返回「0」，這不在你的IN列表中。即您的代碼僅適用於單位數字。你應該採取3個字符然後2個字符長度並修剪空間，但是如果你的樣本中確實有「2UNITS」與「2個單位」的插入，你會遇到更多困難