SQL服務器轉換爲varchar字符串爲int

大家好我有以下存儲過程SQL服務器轉換爲varchar字符串爲int

SELECT DISTINCT QuestionId, AnswerId, COUNT(AnswerId) AS Cntr, 
    (SELECT  COUNT(AnswerId) AS ttl 
    FROM   QUserAnswers 
    WHERE  (QuestionId = QUAM.QuestionId)) AS TtlCnt 
FROM   QUserAnswers AS QUAM 
WHERE  (QuestionId IN (@QuestionIdIn)) 
GROUP BY QuestionId, AnswerId 
ORDER BY QuestionId

我在@QuestionIdI傳遞格式「1,2,3,4,5'然而，它的投擲VARCHAR值'1,2,3,4,5,6'轉換時轉換失敗的錯誤數據類型int。

任何人都可以給我一些指點，如果你擔心服務表現理清

來源

2012-07-26 andrew slaughter

您正在使用什麼版本的SQL Server？ http://www.sommarskog.se/arrays-in-sql-2005.html – 2012-07-26 11:25:04

正如他在其中提供的鏈接，建議由Tim Schelter： -

首先，你需要建立一個分析輸入

CREATE FUNCTION inputParser (@list nvarchar(MAX)) 
RETURNS @tbl TABLE (number int NOT NULL) AS 
BEGIN 
DECLARE @pos  int, 
     @nextpos int, 
     @valuelen int 

SELECT @pos = 0, @nextpos = 1 

WHILE @nextpos > 0 
BEGIN 
    SELECT @nextpos = charindex(',', @list, @pos + 1) 
    SELECT @valuelen = CASE WHEN @nextpos > 0 
          THEN @nextpos 
          ELSE len(@list) + 1 
        END - @pos - 1 
    INSERT @tbl (number) 
    VALUES (convert(int, substring(@list, @pos + 1, @valuelen))) 
    SELECT @pos = @nextpos 
END 
RETURN 
END

然後使用該功能，在您的SP

功能

CREATE PROCEDURE usp_getQuestion 
@QuestionIdIn varchar(50) 
AS 
Begin 
Select Distinct QuestionId, AnswerId, COUNT(AnswerId) AS Cntr, 
    (SELECT  COUNT(AnswerId) AS ttl 
     FROM QUserAnswers 
     WHERE  QuestionId = QUAM.QuestionId) as TtlCnt 
from QUserAnswers AS QUAM 
inner join inputParser (@QuestionIdIn) i ON QuaM.QuestionId = i.number 
GROUP BY QuestionId, AnswerId 
ORDER BY QuestionId 
End 

EXEC usp_getQuestion '1, 2, 3, 4'

來源

2012-07-26 12:22:56 praveen

非常感謝 – 2012-07-26 12:35:27

而不是

WHERE  (QuestionId IN (@QuestionIdIn))

使用

WHERE charindex(','+cast(@QuestionId as varchar(100))+',',','[email protected]+',')>0

，使用分割功能，並與主加盟表

來源

2012-07-26 11:26:31 Madhivanan

只是爲了解釋爲什麼它不起作用：in運算符需要一個表達式列表或一個表。你正在傳遞一個字符串。 – Andreas 2012-07-26 11:28:22

你好，謝謝你，我試着charindex（'，'+ cast（@QuestionId +'，'，'，'+ @ QuestionID +'，'）> 0，它現在說'鑄造'附近有錯誤的語法，預計'AS'。順便說一句，是SqlServer 2005 – 2012-07-26 11:31:11

@andrewslaughter更改'cast（@ QuestionId +'爲'cast（@QuestionId as nvarchar（20））+' – Curt 2012-07-26 11:38:55

試着在這裏應用這個邏輯。

Declare @str varchar(100)='''1'',''2'',''3'',''4'',''5''' 
select @str 
DECLARE @s int = 1 
select * from emp where CAST(@s as varchar) in ('1','2','3','4','5')

來源

2012-07-26 11:44:23 AnandPhadke

試圖改變條件：

WHERE  (QuestionId IN (@QuestionIdIn))

到

where (','[email protected]+',' like '%,'+convert(varchar(50),QuestionId)+',%')

例如，對於@ QuestionIdIn = '1,2,3,4,5,6' 和QuestionId = 3這意味着：

where (',1,2,3,4,5,6,' like '%,3,%')

什麼是真，如果3在這個列表中。

來源

2012-07-26 12:56:04 valex

SQL服務器轉換爲varchar字符串爲int

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