@JsonIgnoreProperties動態數量的參數

Question

我想忽略像

filtervalue0，filtervalue1，filtervalue2性質的數量（這是我從UI獲得）等

我做不過從UI

得到這個數

也就是說，如果filterscount = 3 我知道，會有 filtervalue0，filtervalue1，filtervalue2

是否可以動態地有這樣的工作（即@JsonIgnoreProperties）

Answer 1

您可以使用@JsonFilter動態過濾字段爲Serialization或Deserialization。

例如：

@JsonFilter("myFilter") 
static class Bean { 
    public String filtervalue0 = "a"; 
    public String filtervalue1 = "b"; 
    public int filtercount = 1; 
    public int totalFilters = 2; 
} 

static void test() throws JsonProcessingException{ 
    Bean value = new Bean(); 
    ObjectMapper mapper = new ObjectMapper(); 
    Set<String> filtersToExclude = new HashSet<>(); 

    //logic for applying filter 
    for(int i=value.totalFilters-1; i>value.totalFilters-value.filtercount-1; i--){ 
     filtersToExclude.add("filtervalue"+i); 
    } 

    //dynamic field filtering is provided by FilterProvider 
    FilterProvider filters = new SimpleFilterProvider().addFilter("myFilter", 
     SimpleBeanPropertyFilter.filterOutAllExcept(filtersToExclude)); 
    String json = mapper.setFilterProvider(filters).writeValueAsString(value); 
    System.out.println(json); // prints {"filtervalue1":"b"} 
} 

public static void main(String[] args) throws JsonProcessingException { 
    test(); 
}