2013-05-28 117 views
0

我有這樣的PHP代碼:

$ua = $mysqli->real_escape_string($_SERVER['HTTP_USER_AGENT']); 

$mysqli->query("INSERT INTO browsers(useragent, account, allowed, key, ip) VALUES('$ua', {$userR['id']}, 0, '(Key/token)', '(IP address)')"); 

這是下面的SQL查詢:

INSERT INTO browsers(useragent, account, allowed, key, ip) VALUES('Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.17 (KHTML, like Gecko) Chrome/24.0.1312.56 Safari/537.17', 8, 0, 'bc132b38f35a01ce', '127.0.0.1') 

不過:即使轉義查詢後確實不行:

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'key, ip) VALUES('Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.17 (KHTML, like' at line 1 
+0

請仔細閱讀錯誤:**'key'。 (順便說一句,mysqli的支持預處理語句,就沒有必要逃避值一個接一個。) –

+0

你應該實際參數查詢 –

回答

2

你在你的查詢是使用的是MySQL RESERVED KEYWORD 0,簡單地用反色環繞它`讓數據庫瞭解它是一列

$mysqli->query("INSERT INTO browsers(useragent, account, allowed, `key`, ip) VALUES('$ua', {$userR['id']}, 0, '(Key/token)', '(IP address)')");