獲取DropDownListFor選定值

-1

public class MultipleModel 
{ 
    public Photo Photo { get; set; } 
    public Room Room { get; set; } 
}

：

public class Room 
    { 
     public int Id { get; set; } 
     public string NumberRoom { get; set; } 
     public virtual ICollection<Photo> Photo { get; set; } 
    } 
public class Photo 
    { 
     public int Id { get; set; } 
     public string PhotoName { get; set; } 
     public int Roomid { get; set; } 
     public virtual Room Room { get; set; } 
    }

在點擊Submit在我看來，我要上傳圖片與從名稱的文件夾DropDownListFor所選項目（例如/ images/2 /，其中2 =來自DropDownListFor的ID）並添加到數據庫。我如何使用Html.BeginForm從DropDownListFor正確發送選定的項目？我的觀點：

@using Hotel.BusinessObject 
@model MultipleModel 
@using (Html.BeginForm("AddRoomImg", "Admin", 
     FormMethod.Post, new { enctype = "multipart/form-data", id = Model.Room.Id})) 
{ 
    <div>@Html.DropDownListFor(m=> m.Room.Id, ViewBag.roomlist as SelectList, "Select Room")</div> 

    <input type="file" name="img" /> 
    <input type="submit" value="upload" /> 
}

而且我的控制器，其中Room.Id在formCollection始終= 0和int? id不工作，並返回NULL

 public ActionResult AddRoomImg() 
     { 
      ViewBag.roomlist = new SelectList(db.Room, "Id", "NumberRoom"); 
      return View(); 
     } 
     [HttpPost] 
     public ActionResult AddRoomImg(FormCollection formCollection, int? id) 
     { 
      foreach (string item in Request.Files) 
      { 
       HttpPostedFileBase file = Request.Files[item] as HttpPostedFileBase; 
       if (file.ContentLength == 0) 
        continue; 
       if (file.ContentLength > 0) 
       { 
        ImageUpload imageUpload = new ImageUpload { Width = 600 }; 

        ImageResult imageResult = imageUpload.RenameUploadFile(file); 
        if (imageResult.Success) 
        { 
         //TODO: write the filename to the db 
        } 
        else 
        { 
         ViewBag.Error = imageResult.ErrorMessage; 
        } 
       } 
      }

來源

2015-05-10 Sergey Svezentsev

（1）在'BeginForm（）'方法，'新{ID = Model.Room.Id}'被添加HTML屬性 - 它不清楚是什麼你想用這個（2）你的崗位上做方法簽名應該是'public ActionResult AddRoomImg（MultipleModel model，HttpPostedFileBase img）'和'model.Room.Id'將包含選定的值，'img'將包含該文件。（3）你的''不是多個，所以你爲什麼使用'foreach'循環？（4）使用僅包含視圖中需要顯示/編輯的屬性的視圖模型 –

試試這個

[HttpPost] 
public ActionResult AddRoomImg(MultipleModel model, HttpPostedFileBase img) 
{ 
    //your code here 
}

或

[HttpPost] 
public ActionResult AddRoomImg(MultipleModel model) 
{ 
    var image = Request.Files(0); //access your images 

    //rest of your code here 
}

來源

2015-05-10 15:50:16 warheat1990

我不是想澄清任何事情，我瞭解OP正在嘗試做什麼，並且我給了他答案。 – warheat1990

由於您的問題是關於從dropdownListFor中將選定值轉換爲MultipleModel，首先您應該更新函數參數。

使用MultipleModel model將表單數據導入模型，HttpPostedFileBase img而不是FormCollection formCollection將圖像文件作爲對象。嘗試以下方法。

[HttpPost] 
public ActionResult AddRoomImg(MultipleModel model, HttpPostedFileBase img) 
{ 
    // To get the selected value from dropdownListFor 
    var selectedRoomId = model.Room.Id; 

    // do what you want to do with img object 
    // you will get img.name in the file object that you can rename 
}

來源

2015-05-11 09:56:59

獲取DropDownListFor選定值

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