如果行存在，則更新MySQL表的最快方法否則插入。 2個以上非唯一鍵

Question

我有以下表結構：

CREATE TABLE IF NOT EXISTS `reports` (
    `id` int(11) NOT NULL AUTO_INCREMENT, 
    `day` int(11) NOT NULL, 
    `uid` int(11) NOT NULL, 
    `siteid` int(11) NOT NULL, 
    `cid` int(3) NOT NULL, 
    `visits` int(11) NOT NULL, 
    PRIMARY KEY (`id`) 
) 

目前我請與下面的代碼段&插入/更新：

$checkq = mysql_query("SELECT count(*) as rowexist FROM reports WHERE day='$day' AND uid='$uid' AND siteid='$sid' AND cid='$cid'") or die(mysql_error()); 
$checkr = mysql_fetch_array($checkq); 

if ($checkr['rowexist'] > 0) { 
mysql_query("UPDATE reports_adv SET visits=visits+1 WHERE day='$day' AND uid='$uid' AND siteid='$sid' AND cid='$cid'"); 
} else { 
mysql_query("INSERT INTO reports_adv SET day='$day', uid='$uid', siteid='$sid', cid='$cid', visits='1'"); 
} 

是更新這個MySQL一個最快的方法表是否存在行，否則插入超過2個非唯一鍵？

Answer 1

只使用INSERT...ON DUPLICATE KEY UPDATE

INSERT INTO reports_adv (day, uid, siteid, cid, visits) 
VALUES ('$day', '$uid', '$sid', '$cid', 1) 
ON DUPLICATE KEY UPDATE visits=visits+1; 

• INSERT ... ON DUPLICATE KEY UPDATE Syntax

但任何事情之前，你應該在列定義UNIQUE約束。

ALTER TABLE reports_adv ADD CONSTRAINT tb_uq UNIQUE (day, uid, siteid, cid)