正在驗證我有一個有效的XSD和XML字符串與不同的架構。 如果我使用xml字符串並通過xmldocument.validate
嘗試使用xsd模式進行驗證,則不驗證。用於測試books-debug.xml
XML字符串不是XSD
dim tmpdoc as new xmldocument()
dim abc as string= file.readalltext("books-debug.xml")
tmpdoc.schemas.add(nothing,"New.xsd")
Dim eventHandler As New ValidationEventHandler(AddressOf ValidationEventHandler)
tmpDoc.Validate(eventHandler)
End Sub
Private Shared Sub ValidationEventHandler(ByVal sender As Object, ByVal e As ValidationEventArgs)
Select Case e.Severity
Case XmlSeverityType.[Error]
MessageBox.Show("Error: {0}" + e.Message)
Exit Select
Case XmlSeverityType.Warning
MessageBox.Show("Warning {0}" + e.Message)
Exit Select
End Select
End Sub
XML:
<?xml version="1.0" encoding="UTF-8" ?>
<bookstore xmlns="http://myspace">
<debugparameters>
<parameter>
<paramname>paramname1</paramname>
<description>description1</description>
<subsystems>
<subsystem-id>g</subsystem-id>
<subsystem-id>f</subsystem-id>
<subsystem-id>d</subsystem-id>
</subsystems>
</parameter>
<parameter>
<paramname>paramname2</paramname>
<description>description2</description>
<subsystems>
<subsystem-id>f</subsystem-id>
<subsystem-id>g</subsystem-id>
<subsystem-id>d</subsystem-id>
</subsystems>
</parameter>
<parameter>
<paramname>paramname3</paramname>
<description>description3</description>
<subsystems>
<subsystem-id>f</subsystem-id>
<subsystem-id>g</subsystem-id>
<subsystem-id>d</subsystem-id>
</subsystems>
</parameter>
</debugparameters>
</bookstore>
的xsd:
<?xml version="1.0" encoding="utf-8"?>
<xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" targetNamespace="http://www.contoso.com/books" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:element name="bookstore">
<xs:complexType>
<xs:sequence>
<xs:element maxOccurs="unbounded" name="book">
<xs:complexType>
<xs:sequence>
<xs:element name="title" type="xs:string" />
<xs:element name="writer">
<xs:complexType>
<xs:sequence>
<xs:element minOccurs="0" name="name" type="xs:string" />
<xs:element minOccurs="0" name="first-name" type="xs:string" />
<xs:element minOccurs="0" name="last-name" type="xs:string" />
</xs:sequence>
</xs:complexType>
</xs:element>
<xs:element name="price" type="xs:decimal" />
</xs:sequence>
<xs:attribute name="genre" type="xs:string" use="required" />
<xs:attribute name="publicationdate" type="xs:date" use="required" />
<xs:attribute name="ISBN" type="xs:string" use="required" />
</xs:complexType>
</xs:element>
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:schema>
你的XML中只有一個共同的與你的XML元素。你確定這是正確的實例或模式?命名空間也完全不同。 – helderdarocha
查看下面的模式是否解決了您的問題。如果沒有,請用它編輯您的問題(因爲您發佈的內容不兼容)。 – helderdarocha
謝謝你的回覆...我的問題是爲什麼我沒有得到任何錯誤,即使架構不同於xml – projectTesting