將開關語句更改爲兩個或更多函數，每個函數

-3

對於3個開關語句，我將用兩個或多個函數調用替換每個switch語句。這是爲了在上個學期開始的C++類中取代「不完整的」，這樣我就可以獲得貸款，並且我不知道從哪裏開始。將開關語句更改爲兩個或更多函數，每個函數

我試着把開關語句放到自己的函數中，只是把開關語句本身放在它們自己的函數中，當然，這也產生了大量的語法錯誤（例如counter，random_number）。我不知道該怎麼做，如何將適當的值返回到main()，並讓程序與程序的其他部分（例如，主要定義/初始化的變量）進行通信。正如人們所看到的那樣，我只是迷失在這裏，希望得到一些指導來解決這個問題。我沒有要求任何人爲我做這件事，只是一些指導（我對C++的知識是有限的，並且有時間限制）。

// random.cpp : Defines entry point for the console application. 
// 

#include <iostream> 
#include <iomanip> 
#include <string> 
#include <stdio.h> 
#include <stdlib.h> 
#include <time.h> 
using namespace std; 

//random number generator prototypes 
void randomize(void); 
void randomize(int seed); 
int random(void); 
int random(int upper_bound); 
int random(int upper_bound, int lower_bound); 

int main() 
{ 
int upper_bound = 999; 
int lower_bound = 100; 
int n_random_numbers = 1000; 

randomize(); 

int counter_0 = 0; 
int counter_1 = 0; 
int counter_2 = 0; 
int counter_3 = 0; 
int counter_4 = 0; 
int counter_5 = 0; 
int counter_6 = 0; 
int counter_7 = 0; 
int counter_8 = 0; 
int counter_9 = 0; 

for(int counter = 1; counter <= n_random_numbers; counter++) 
{ 
    int random_number = random(upper_bound, lower_bound); 
    int digit_1 = random_number % 10; random_number = random_number/10; 
    switch(digit_1) 
    { 
     case 0: 
      counter_0++; 
      break; 
     case 1: 
      counter_1++; 
      break; 
     case 2: 
      counter_2++; 
      break; 
     case 3: 
      counter_3++; 
      break; 
     case 4: 
      counter_4++; 
      break; 
     case 5: 
      counter_5++; 
      break; 
     case 6: 
      counter_6++; 
      break; 
     case 7: 
      counter_7++; 
      break; 
     case 8: 
      counter_8++; 
      break; 
     case 9: 
      counter_9++; 
      break; 
    } 
    int digit_2 = random_number % 10; random_number = random_number/10; 
    switch(digit_2) 
    { 
     case 0: 
      counter_0++; 
      break; 
     case 1: 
      counter_1++; 
      break; 
     case 2: 
      counter_2++; 
      break; 
     case 3: 
      counter_3++; 
      break; 
     case 4: 
      counter_4++; 
      break; 
     case 5: 
      counter_5++; 
      break; 
     case 6: 
      counter_6++; 
      break; 
     case 7: 
      counter_7++; 
      break; 
     case 8: 
      counter_8++; 
      break; 
     case 9: 
      counter_9++; 
      break; 
    } 

    int digit_3 = random_number % 10; random_number = random_number/10; 
    switch(digit_3) 
    { 
     case 0: 
      counter_0++; 
      break; 
     case 1: 
      counter_1++; 
      break; 
     case 2: 
      counter_2++; 
      break; 
     case 3: 
      counter_3++; 
      break; 
     case 4: 
      counter_4++; 
      break; 
     case 5: 
      counter_5++; 
      break; 
     case 6: 
      counter_6++; 
      break; 
     case 7: 
      counter_7++; 
      break; 
     case 8: 
      counter_8++; 
      break; 
     case 9: 
      counter_9++; 
      break; 
    } 

} 
cout << "0 occurs " << counter_0 << " times" << endl; 
cout << "1 occurs " << counter_1 << " times" << endl; 
cout << "2 occurs " << counter_2 << " times" << endl; 
cout << "3 occurs " << counter_3 << " times" << endl; 
cout << "4 occurs " << counter_4 << " times" << endl; 
cout << "5 occurs " << counter_5 << " times" << endl; 
cout << "6 occurs " << counter_6 << " times" << endl; 
cout << "7 occurs " << counter_7 << " times" << endl; 
cout << "8 occurs " << counter_8 << " times" << endl; 
cout << "9 occurs " << counter_9 << " times" << endl; 

system("pause"); 

return 0; 
} 

//random number generators 
void randomize(void) 
{ 
srand(unsigned(time(NULL))); 
} 

void randomize(int seed) 
{ 
srand(unsigned(seed)); 
} 

int random(void) 
{ 
return rand(); 
} 

int random(int upper_bound) 
{ 
return rand() % (upper_bound + 1); 
} 

int random(int upper_bound, int lower_bound) 
{ 
    if(upper_bound < lower_bound) 
     { 
    int t = upper_bound; 
    upper_bound = lower_bound; 
    lower_bound = t; 
     } 
int range = upper_bound - lower_bound + 1; 
int number = rand() % range + lower_bound; 
return number; 
}

我添加了這些功能，看看它是否會工作（圖1.1）（我加counter，upper_bound，lower_bound，n_random_numbers因爲我無法弄清楚如何具有的功能從main()讀這些變量。我嘗試將它們變成一個函數，在main函數中調用它們，然後在我創建的函數中調用它們，但那肯定不起作用，這些增加的函數用函數調用代替原來的函數中的開關（參見圖1.2）。編譯，但輸出返回「0出現0次，1出現0次，等等」。

圖1.1

int switch1 (int switch_1) 
{ 
int upper_bound = 999; 
int lower_bound = 100; 
int n_random_numbers = 1000; 
int counter = 0; 

randomize(); 

int counter_0 = 0; 
int counter_1 = 0; 
int counter_2 = 0; 
int counter_3 = 0; 
int counter_4 = 0; 
int counter_5 = 0; 
int counter_6 = 0; 
int counter_7 = 0; 
int counter_8 = 0; 
int counter_9 = 0; 

int random_number = random(upper_bound, lower_bound); 

int digit_1 = random_number % 10; random_number = random_number/10; 
    switch(digit_1) 
    { 
     case 0: 
      counter_0++; 
      break; 
     case 1: 
      counter_1++; 
      break; 
     case 2: 
      counter_2++; 
      break; 
     case 3: 
      counter_3++; 
      break; 
     case 4: 
      counter_4++; 
      break; 
     case 5: 
      counter_5++; 
      break; 
     case 6: 
      counter_6++; 
      break; 
     case 7: 
      counter_7++; 
      break; 
     case 8: 
      counter_8++; 
      break; 
     case 9: 
      counter_9++; 
      break; 
    } 

} 

int switch2 (int switch_2) 
{ 
int upper_bound = 999; 
int lower_bound = 100; 
int n_random_numbers = 1000; 
int counter = 0; 

randomize(); 

int counter_0 = 0; 
int counter_1 = 0; 
int counter_2 = 0; 
int counter_3 = 0; 
int counter_4 = 0; 
int counter_5 = 0; 
int counter_6 = 0; 
int counter_7 = 0; 
int counter_8 = 0; 
int counter_9 = 0; 

int random_number = random(upper_bound, lower_bound); 

int digit_2 = random_number % 10; random_number = random_number/10; 
    switch(digit_2) 
    { 
     case 0: 
      counter_0++; 
      break; 
     case 1: 
      counter_1++; 
      break; 
     case 2: 
      counter_2++; 
      break; 
     case 3: 
      counter_3++; 
      break; 
     case 4: 
      counter_4++; 
      break; 
     case 5: 
      counter_5++; 
      break; 
     case 6: 
      counter_6++; 
      break; 
     case 7: 
      counter_7++; 
      break; 
     case 8: 
      counter_8++; 
      break; 
     case 9: 
      counter_9++; 
      break; 
    } 

} 

int switch3 (int switch_3) 
{ 
int upper_bound = 999; 
int lower_bound = 100; 
int n_random_numbers = 1000; 
int counter = 0; 

randomize(); 

int counter_0 = 0; 
int counter_1 = 0; 
int counter_2 = 0; 
int counter_3 = 0; 
int counter_4 = 0; 
int counter_5 = 0; 
int counter_6 = 0; 
int counter_7 = 0; 
int counter_8 = 0; 
int counter_9 = 0; 

int random_number = random(upper_bound, lower_bound); 

int digit_3 = random_number % 10; random_number = random_number/10; 
    switch(digit_3) 
    { 
     case 0: 
      counter_0++; 
      break; 
     case 1: 
      counter_1++; 
      break; 
     case 2: 
      counter_2++; 
      break; 
     case 3: 
      counter_3++; 
      break; 
     case 4: 
      counter_4++; 
      break; 
     case 5: 
      counter_5++; 
      break; 
     case 6: 
      counter_6++; 
      break; 
     case 7: 
      counter_7++; 
      break; 
     case 8: 
      counter_8++; 
      break; 
     case 9: 
      counter_9++; 
      break; 
    } 

}

圖1.2

for(int counter = 1; counter <= n_random_numbers; counter++) 
{ 
    int random_number = random(upper_bound, lower_bound); 
    int digit_1 = random_number % 10; random_number = random_number/10; 
    int digit_2 = random_number % 10; random_number = random_number/10; 
    int digit_3 = random_number % 10; random_number = random_number/10; 

switch1 (digit_1); 
switch2 (digit_2); 
switch3 (digit_3); 

}

來源

2012-02-26 Danny

你應該讀好C++的書，瞭解數組，向量，和一般的集合。做任何你想做的事情都有更好的方法。 – Mat 2012-02-26 19:18:33

@Mat - 我確定有更好的方法來完成這個任務，但是這個任務專門用來「用兩個或多個函數調用替換每個switch語句」。這就是我以這種方式提出問題的原因。 – Danny 2012-02-26 19:21:35

如果您要爲我們發佈一個任務，您至少可以發佈需求的全文，而不僅僅是重複的「用兩個或多個函數調用替換每個switch語句」的短語。 – 2012-02-26 19:31:37

需要任何開關：

int counters[10] = {}; 

for(int counter = 1; counter <= n_random_numbers; counter++) 
{ 
    int random_number = random(upper_bound, lower_bound); 
    int digit_1 = random_number % 10; random_number = random_number/10; 
    ++counters[digit_1]; 

    int digit_2 = random_number % 10; random_number = random_number/10; 
    ++counters[digit_2]; 

    int digit_3 = random_number % 10; random_number = random_number/10; 
    ++counters[digit_3]; 
}

來源

2012-02-26 19:19:40 ronag

雖然你的解決方案非常乾淨，並且是一種更好的編程方式，但我確定，這個任務專門用於「用兩個或更多函數調用替換每個開關語句」，正如教授的指令所定義的（我知道這很愚蠢）。不過謝謝你。 – Danny 2012-02-26 19:22:47

「用兩個或多個函數調用替換每個switch語句」，並不合理...... – ronag 2012-02-26 19:29:27

指令對我來說似乎也很奇怪。以上面的數組和'for'語句，如何將其放入函數中？你會返回什麼程序？那麼函數中的'random（upper_bound，lower_bound）'函數將被讀取？你可以在一個函數內調用一個函數嗎？ – Danny 2012-02-26 19:39:29

將開關語句更改爲兩個或更多函數，每個函數

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