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Iam尋找jQuery的PHP圖像上傳完全給出http://valums.com/ajax-upload/。 我試着在上面的網站給出的代碼。但它不起作用。作爲IAM新手..我試着下面的代碼。jquery php上傳使用http://valums.com/ajax-upload/
<?php
$uploaddir = 'c:\xampp\htdocs\ajax-upload\server\uploads\';
$uploadfile = $uploaddir . basename($_FILES['file']['name']);
if (move_uploaded_file($_FILES['file']['tmp_name'], $uploadfile)) {
echo "success";
} else {
// WARNING! DO NOT USE "FALSE" STRING AS A RESPONSE!
// Otherwise onSubmit event will not be fired
echo "error";
}
?>
這是在PHP改變我的html代碼
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<link href="fileuploader.css" rel="stylesheet" type="text/css">
<style>
body {font-size:13px; font-family:arial, sans-serif; width:700px; margin:100px auto;}
</style>
</head>
<body>
<p><a href="http://github.com/valums/file-uploader">Back to project page</a></p>
<p>To upload a file, click on the button below. Drag-and-drop is supported in FF, Chrome.</p>
<p>Progress-bar is supported in FF3.6+, Chrome6+, Safari4+</p>
<div id="file-uploader-demo1">
<noscript>
<p>Please enable JavaScript to use file uploader.</p>
<!-- or put a simple form for upload here -->
</noscript>
</div>
<script src="fileuploader.js" type="text/javascript"></script>
<script>
function createUploader(){
var uploader = new qq.FileUploader({
element: document.getElementById('file-uploader-demo1'),
action: '../server/upload.php',
debug: true
});
}
// in your app create uploader as soon as the DOM is ready
// don't wait for the window to load
window.onload = createUploader;
</script>
</body>
</html>
「不工作」是什麼意思? – jprofitt
我們可以看到您的完整html代碼請 – Satya
如果您將第一行更改爲$ uploaddir ='/ uploads /';那樣有用嗎?當使用本地主機時,您可以通過(我猜)xampp進行訪問,並且上傳目錄也應該使用您的xampp。你是否也嘗試過查看控制檯返回的內容? (調試真正的任何錯誤記錄到控制檯) – scott