如果未手動賦值，則浮點值不起作用

我需要檢查百分比變化是否大於0，是否爲0,<和NULL。所以我就返回SELECT語句的結果get_count（）...：如果未手動賦值，則浮點值不起作用

get_count() { 
    sqlplus -s un/pass <<! 
    set heading off 
    set feedback off 
    set pages 0 
    select trunc(PRNCT_CHANGE, 3) 
    FROM SEMANTIC.COUNT_STATISTICS; 
    exit; 
! 
} 

count=$(get_count $1) #possible values: -0.789, -10.999, 11.897, 20, 1, 0... 

if [ -z "$count" ]; then 
    echo "The count percentage change returns null value" 
elif [[ "$count" -gt 0 ]]; then 
    echo "The count percentage change ($count) is greater than zero" 
elif [[ "$count" == 0 ]]; then 
    echo "The count percentage change stays unchanged (is zero)" 
elif [[ "$count" =~ ^[\-0-9] ]]; then 
    echo "The count percentage change is $count" 
else 
    echo "$count ... Something else is wrong here" 
fi

如果我手動分配值$count即：

count=-0.987

這是偉大的工作。

否則，如果我讓get_count（）方法返回的值，它總是跳轉到else聲明...

我應該轉換得到數據傳遞給$count變量莫名其妙的價值..？

來源

2013-11-25 Angelina

您的'get_count'實際上並未使用傳遞給它的參數。 – chepner

是的...我明白了價值。因爲它會得到迴應：「-71.888 ...此處有其他錯誤」 – Angelina

是你的意思嗎？ @chepner – Angelina

bash不理解浮點值。您需要使用外部程序（如bc）來進行比較：

if [ -z "$count" ]; then 
    echo "The count percentage change returns null value" 
elif [[ $(echo "$count > 0" | bc) -eq 1 ]]; then 
    echo "The count percentage change ($count) is greater than zero" 
elif [[ $(echo "$count < 0" | bc) -eq 1 ]]; then 
    echo "The count percentage change ($count) is less than zero" 
elif [[ "$count" == 0 ]]; then 
    echo "The count percentage change stays unchanged (is zero)" 
else 
    echo "$count ... Something else is wrong here" 
fi

來源

2013-11-25 21:12:03 chepner

如果未手動賦值，則浮點值不起作用

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