分裂在VB.NET

Question

使用正則表達式我有格式的字符串數值的字符串：

"one two 33 three" 

我需要將其分裂上的數字值，使得我得到長度爲2的數組：

"one two" 
"33 three" 

或長度3的數組：

"one two" 
"33" 
"three" 

我試圖Regex.Split(str,"\D+")但它給了我：

"" 
"33" 
"" 

和Regex.Split(str,"\d+")遞給我：

"one two" 
"three" 

和Regex.Split(str,"\d")遞給我：

"one two" 
"" 
"three" 

所以沒有給我想要的結果。誰能幫忙？

Answer 1

(?=\b\d+\b) 

拆分這個正則表達式。

這使用積極的前瞻來檢查是否在分裂點有一個整數分隔的字邊界。參見演示。

https://regex101.com/r/wV5tP1/5

編輯：

如果你想刪除的空間也利用

(?=\d+\b)

觀看演示。

https://regex101.com/r/wV5tP1/6

Answer 2

使用在您的正則像一個前瞻，

Regex.Split(str," (?=\d+)") 

(?=\d+)正預測先行斷言，這場比賽必須遵循的一個數字。所以上面的正則表達式會匹配前面存在的空格。根據匹配的空間分割會給你"one two" "33 three"作爲結果。

Dim input As String = "one two 33 three" 
Dim pattern As String = " (?=\d+)" 
Dim substrings() As String = Regex.Split(input, pattern) 
For Each match As String In substrings 
    Console.WriteLine("'{0}'", match) 
Next 

輸出：

'one two' 
'33 three' 

IDEONE

爲了獲得長度的數組3.

Public Sub Main() 
Dim input As String = "one two 33 three" 
Dim pattern As String = " (?=\d+)|(?<=\b\d+) " 
Dim substrings() As String = Regex.Split(input, pattern) 
For Each match As String In substrings 
Console.WriteLine("'{0}'", match) 

輸出：

'one two' 
'33' 
'three' 

IDEONE