1
當我嘗試編輯聯繫人以添加DataType時,我收到:'未經許可的參數:data_format'錯誤。我嘗試過以下類似的聯繫,但我無法弄清楚我缺少的東西。如果這是多餘的,我很抱歉。何處允許has_one/belongs_to關聯中的參數?
這裏是信息的相關部分:
型號:
# == Schema Information
#
# Table name: contacts
#
# id :integer not null, primary key
# name :string
# email :string
# phone :string
# mobile :string
# created_at :datetime not null
# updated_at :datetime not null
# supplier_id :integer
#
class Contact < ActiveRecord::Base
has_one :data_type
accepts_nested_attributes_for :data_type, allow_destroy: true
end
# == Schema Information
#
# Table name: data_formats
#
# id :integer not null, primary key
# name :string
# created_at :datetime not null
# updated_at :datetime not null
# contact_id :integer
#
class DataFormat < ActiveRecord::Base
belongs_to :contact
end
聯繫控制器:
class ContactsController < ApplicationController
before_action :set_contact, only: [:show, :edit, :update, :destroy]
def new
@contact = Contact.new
end
def create
@contact = Contact.new(contact_params)
respond_to do |format|
if @contact.save
format.html { redirect_to @contact, notice: 'Contact was successfully created.' }
format.json { render :show, status: :created, location: @contact }
else
format.html { render :new }
format.json { render json: @contact.errors, status: :unprocessable_entity }
end
end
end
private
def set_contact
@contact = Contact.find(params[:id])
end
def contact_params
params.require(:contact).permit(:name, :email, :phone, :mobile, :data_format,
data_format_attributes: [ :id, :name, :contact_id, :_destroy ])
end
end
編輯觀點:
<%= simple_form_for @contact do |f| %>
<div class="form-group">
<div class="col-lg-6">
<%= f.input :name %>
</div>
<div class="col-lg-6">
<%= f.simple_fields_for :data_format do |t| %>
<%= t.input :id, label: 'Date Format:', :collection => DataFormat.order(:name) %>
<% end %>
</div>
<div class="col-lg-6">
<%= f.label "Submit", class: 'control-label' %>
<%= f.button :submit, class: 'btn btn-primary form-control' %>
</div>
</div>
<% end %>
DataType(s)出現在窗體中,我可以選擇它們。所以,我知道這個問題必須在控制器內。
任何幫助將不勝感激!
嘿!感謝您的答覆!完成這些更正後,我的輸入字段消失。有什麼建議麼? – nkulig
您還需要在''new'''動作中'''build''',以便從中加載表單的對象實例。我已經更新了答案。看看是否有幫助。 – shayonj
嘿!我也偶然發現了這一點。但是,輸入仍然沒有顯示出來。 – nkulig