替換字符串包含雙qoutes和結腸

我有這個字符串保存在$metaV：替換字符串包含雙qoutes和結腸

{"feedName":"Paypal Test","paypalEmail":"[email protected]","mode":"test","transactionType":"subscription","recurringAmount":"form_total","billingCycle_length":"1","billingCycle_unit":"day","recurringTimes":"0","recurringRetry":"0","trial_enabled":"1","trial_product":"73","trial_amount":"","trialPeriod_length":"1","trialPeriod_unit":"month","billingInformation_firstName":"4","billingInformation_lastName":"27","billingInformation_email":"5","billingInformation_address":"","billingInformation_address2":"","billingInformation_city":"","billingInformation_state":"","billingInformation_zip":"34","billingInformation_country":"","pageStyle":"","continueText":"","cancelUrl":"","disableShipping":"0","disableNote":"0","delayNotification":"0","selectedNotifications":"","feed_condition_conditional_logic":"0","feed_condition_conditional_logic_object":{"conditionalLogic":{"actionType":"show","logicType":"all","rules":[{"fieldId":"73","operator":"is","value":"1 month"}]}},"type":"subscription","recurring_amount_field":"form_total","update_user_action":"","delay_registration":"","update_site_action":""}

我想替換字符串的這一部分：

"trial_enabled":"0"

我試圖用str_replace()此：

str_replace('\"trial_enabled\":\"1\"', '\"trial_enabled\":\"0\"',$metaV);

來源

2016-03-15 akash ujjwal

你在這裏是一個JSON字符串。請參閱：http://stackoverflow.com/q/29308898/3933332如何訪問這些數據並將其存入數組。這樣可以更容易地修改信息。現在你正試圖以錯誤的方式解決問題。 – Rizier123

@ Rizier123噢，是的，我以錯誤的方式去做。感謝您的建議。 –

您可以使用json_decode和json_encode將您的字符串轉換爲數組並返回。

$data = json_decode($metaV, true); 
$data['trial_enabled'] = "1"; 
$metaV = json_encode($data);

來源

2016-03-15 18:08:33 Philipp

謝謝你！它的作品!! ...但我試過它作爲 $ metaV = explode（'，'，$ meta）; $ metaV [9] ='「trial_enabled」：「0」'; $ metaV = implode（'，'，$ metaV）; 但是你的解決方案就像魅力一樣工作。再次感謝。 –

替換字符串包含雙qoutes和結腸

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