Rails活動記錄ID與對象ID +活動::關係

Question

我一直在收到這樣的消息：

警告：對象＃id將被棄用;使用對象＃OBJECT_ID

我閱讀和Ruby Object#id warnings and Active Record嘗試的招數沒有成功：

108-125-94-123:toptickets johnnygoodman$ rails c 
Loading development environment (Rails 3.0.3) 
>> ticket_id = 8899 
=> 8899 
>> ticket = Ticket.where(:number => ticket_id) 
=> [#<Ticket id: 97, name: "Set Up API to Feed Customer Info into Bronto ", number: "8899", category_id: 15, created_at: "2011-01-31 21:24:29", updated_at: "2011-01-31 21:24:29", position: 20>] 
>> ticket.id 
(irb):3: warning: Object#id will be deprecated; use Object#object_id 
=> 2175680980 
>> ticket[:id] 
TypeError: Symbol as array index 
     from /Library/Ruby/Gems/1.8/gems/activerecord-3.0.3/lib/active_record/relation.rb:363:in `[]' 
     from /Library/Ruby/Gems/1.8/gems/activerecord-3.0.3/lib/active_record/relation.rb:363:in `send' 
     from /Library/Ruby/Gems/1.8/gems/activerecord-3.0.3/lib/active_record/relation.rb:363:in `method_missing' 
     from (irb):4 
>> ticket.class 
=> ActiveRecord::Relation 

我希望，當我詢問門票這將是一流的ActiveRecord ::基地。我不知道該怎麼做才能實現這一目標，或者我應該向哪個方向發展。

目標：查詢票證，打印其ID。在上面的例子中，ID的值應該是97.

Answer 1

ticket = Ticket.where(:number => ticket_id)返回一個ActiveRecord :: Relation（在IRB中計算時，執行數據庫查詢並返回一個票證數組）。所以ticket.id正試圖對整個票證數組執行.id，而不是一個實際的票證。

也許你只想要第一個結果？

>> ticket = Ticket.where(:number => ticket_id).first 
>> puts ticket.id 
=> 97