過濾活動記錄關係

我有一個有效性的類過濾活動記錄關係

class Availability < ActiveRecord::Base 
    # Associations 
    belongs_to :facility 
    has_one :venue, through: :facility 
end

那堂課我有一個搜索方法，我在我的控制器調用這樣的：

@search = Availability.search(params, get_location)

def self.search(params, location) 
    perform_search(location, params[:activity], params[:start_time], params[:end_time],params[:period]) 
    end 

    def self.perform_search(location, activity, start_time, end_time, period) 
    self 
     .not_booked 
     .after_now 
     .close_to(Venue.close_to(location)) 
     .activity(Activity.find_by_name activity) 
     .start_date(validate_start_time start_time) 
     .end_date(validate_end_time end_time) 
     .within_segment_of_day(period) 
     .sorted 
    end

問題：我現在需要添加一個額外的過濾器。每個場地都有自己的最短時間（notice_time:integer type），然後才能預訂可用性。

For example: You can only book an availability as long as we have 48 hour notice from the start time

我試圖通過添加新的範圍，以實現這一點：

scope :after_notice_time, -> {joins{venue}.where{start_time >= (venue.notice_time.hours.from_now)}}

，但得到錯誤：

[58] pry(main)> Availability.after_notice_time
Availability Load (4.9ms) SELECT "availabilities".* FROM "availabilities" INNER JOIN "facilities" ON "facilities"."id" = "availabilities"."facility_id" INNER JOIN "venues" ON "venues"."id" = "facilities"."venue_id" WHERE "availabilities"."start_time" >= "hours"."from_now"

PG::UndefinedTable: ERROR: missing FROM-clause entry for table "hours" LINE 1: ..."venue_id" WHERE "availabilities"."start_time" >= "hours"."f... ^: SELECT "availabilities".* FROM "availabilities" INNER JOIN "facilities" ON "facilities"."id" = "availabilities"."facility_id" INNER JOIN "venues" ON "venues"."id" = "facilities"."venue_id" WHERE "availabilities"."start_time" >= "hours"."from_now" => # < Availability::ActiveRecord_Relation:0x5b525ac>

如何篩選結果，這樣我可以檢查每個可用性venue.notice_time，並確保我的最終@search僅包含start_time大於01的可用性

來源

2015-11-10 Batman

你可以嘗試這樣的事情用簡單的SQL（此代碼是PG特定）：在Reddit上

scope :after_notice_time, 
-> { joins(:venue) 
.where("start_time >= (current_timestamp + venues.notice_time * interval '1 hour') }

來源

2015-11-10 16:24:23 ehoffmann

有人給了我這個解決方案，它是幾乎等同於你：'加入（：場地）。 where（「start_time> = now（）+ venues.notice_time *'1 hour':: interval」）'這似乎是完美的 – Batman

過濾活動記錄關係

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