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主要我有一個JSON文件格式如下:如何獲取一個JSON文件與SimpleJson C#
{
"3874D632": {
"FirstName": "Jack",
"LastName": "Andersen"
},
"34F43A33": {
"FirstName": "John",
"LastName": "Smith"
}
}
StreamReader read_json = new StreamReader(path_json_file);
json = JSONNode.Parse(read_json.ReadToEnd());
read_json.Close();
如何獲取3874D632或34F43A33?
json[????].
看一看在Unity3D維基:http://wiki.unity3d.com/index.php/SimpleJSON – elgonzo