4
我對JavaScript本功能,工作在Firefox,但在谷歌瀏覽器不DOM對象的構造不能作爲函數調用
function sendInfo(userId, Code) {
// text with all info to send to controller
var values = {
"token": Code,
"code": userId
}
// POST THE CHANGE HERE TO THE DATABASE
var url = "WSHolFacebook.asmx/saveToken";
$.post(url, values, function (data) {
if (window.ActiveXObject) { return data.xml; }
var xmlString = XMLSerializer().serializeToString(data);
var xml = xmlString,
xmlDoc = $.parseXML(xml),
$xml = $(xmlDoc),
$title = $xml.find("string");
var texto = $title.text();
if ($title.text() == "Success") {
window.location = '<%=ConfigurationManager.AppSettings["successUrl"].ToString() %>'
}
else {
window.location = '<%=ConfigurationManager.AppSettings["errorUrl"].ToString() %>'
}
})
}
中鉻的錯誤是:
Uncaught TypeError: DOM object constructor cannot be called as a function.
這是,謝謝你,我在這個問題上失去了很多時間,因爲一個新的!再次感謝 – kaub0st3r 2013-03-22 15:47:53