將XML轉換爲分層格式的XSLT

Question

我有一個xml，其中有一個簡單形式的partyId和parentPartyId值。我想將它轉換成分層樹格式的形式。

我已根據所需的輸出創建了架構。我正在嘗試使用http://www.keller.com/xslt/8/中的Axis名稱表達式。我沒有得到，如何將源代碼轉換爲所需的格式？

來源和要求的目標如下。

來源：

<OutputCollection xmlns="http://xmlns.test.com/pcbpel/adapter/db/PartyHierarchy"> 
      <Output> 
       <level>1</level> 
       <Parent_Party xsi:nil="true"/> 
       <Party>Party-1</Party> 
      </Output> 
      <Output> 
       <level>2</level> 
       <Parent_Party>Party-1</Parent_Party> 
       <Party>Party-1-1</Party> 
      </Output> 
      <Output> 
       <level>2</level> 
       <Parent_Party>Party-1</Parent_Party> 
       <Party>Party-1-2</Party> 
      </Output> 
      <Output> 
       <level>3</level> 
       <Parent_Party>Party-1-2</Parent_Party> 
       <Party>Party-1-2-1</Party> 
      </Output> 
      <Output> 
       <level>3</level> 
       <Parent_Party>Party-1-2</Parent_Party> 
       <Party>Party-1-2-2</Party> 
      </Output> 
      <Output> 
       <level>3</level> 
       <Parent_Party>Party-1-2</Parent_Party> 
       <Party>Party-1-2-3</Party> 
      </Output> 
      <Output> 
       <level>2</level> 
       <Parent_Party>Party-1</Parent_Party> 
       <Party>Party-1-3</Party> 
      </Output> 
      <Output> 
       <level>3</level> 
       <Parent_Party>Party-1-3</Parent_Party> 
       <Party>Party-1-3-1</Party> 
      </Output> 
      <Output> 
       <level>3</level> 
       <Parent_Party>Party-1-3</Parent_Party> 
       <Party>Party-1-3-2</Party> 
      </Output> 
     </OutputCollection> 

目標：

<OutputCollection xmlns="http://xmlns.test.com/pcbpel/adapter/db/PartyHierarchy"> 
      <Output> 
       <level>1</level> 
       <Parent_Party xsi:nil="true"/> 
       <Party>Party-1</Party> 
       <Children> 
        <level>2</level> 
        <Parent_Party>Party-1</Parent_Party> 
        <Party>Party-1-1</Party> 
       </Children> 
       <Children> 
        <level>2</level> 
        <Parent_Party>Party-1</Parent_Party> 
        <Party>Party-1-2</Party> 
        <Children> 
         <level>3</level> 
         <Parent_Party>Party-1-2</Parent_Party> 
         <Party>Party-1-2-1</Party> 
        </Children> 
        <Children> 
         <level>3</level> 
         <Parent_Party>Party-1-2</Parent_Party> 
         <Party>Party-1-2-2</Party> 
        </Children> 
        <Children> 
         <level>3</level> 
         <Parent_Party>Party-1-2</Parent_Party> 
         <Party>Party-1-2-3</Party>     
        </Children> 
       </Children> 
       <Children> 
        <level>2</level> 
        <Parent_Party>Party-1</Parent_Party> 
        <Party>Party-1-3</Party> 
        <Children> 
         <level>3</level> 
         <Parent_Party>Party-1-3</Parent_Party> 
         <Party>Party-1-3-1</Party>     
        </Children> 
        <Children> 
         <level>3</level> 
         <Parent_Party>Party-1-3</Parent_Party> 
         <Party>Party-1-3-2</Party>   
        </Children>     
       </Children> 
      </Output> 
     </OutputCollection> 

Answer 1

使用XSLT，如果你需要遵循交叉引用，那麼你需要定義一個關鍵<xsl:key name="children" match="ph:Output" use="ph:Parent_Party"/>並使用它<xsl:apply-templates select="key('children', ph:Party)"/>：

<xsl:stylesheet 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    xmlns:ph="http://xmlns.test.com/pcbpel/adapter/db/PartyHierarchy" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns="http://xmlns.test.com/pcbpel/adapter/db/PartyHierarchy" 
    exclude-result-prefixes="ph xsi" 
    version="1.0"> 

<xsl:output indent="yes"/> 
<xsl:strip-space elements="*"/> 

<xsl:key name="children" match="ph:Output" use="ph:Parent_Party"/> 

<xsl:template match="/*"> 
    <xsl:copy> 
    <xsl:apply-templates select="key('children', '')"/> 
    </xsl:copy> 
</xsl:template> 

<xsl:template match="ph:Output[ph:Parent_Party/@xsi:nil = 'true']"> 
    <xsl:copy> 
    <xsl:copy-of select="node()"/> 
    <xsl:apply-templates select="key('children', ph:Party)"/> 
    </xsl:copy> 
</xsl:template> 

<xsl:template match="ph:Output"> 
    <children> 
    <xsl:copy-of select="node()"/> 
    <xsl:apply-templates select="key('children', ph:Party)"/> 
    </children> 
</xsl:template> 

</xsl:stylesheet> 

請注意，您發佈的輸入示例使用前綴xsi，但未聲明它，因此我不得不假定該前綴的名稱空間。