我有三條精選語句,除了每個事件的平均「分數」和每個事件的計數之外,還提供了出席特定事件(醫療保健,宗教和運動)的成員數量。梳理精選語句
每個事件的計數都不相同。
單獨的每個查詢都有效,但我想將它們組合成一個查詢。
我該怎麼做?
(select sum(case when Healthcare ='1' then 1 else 0 end) as [Healthcare_never],
sum(case when Healthcare ='2' then 1 else 0 end) as [Healthcare_not often],
sum(case when Healthcare ='3' then 1 else 0 end) as [Healthcare_average],
sum(case when Healthcare ='4' then 1 else 0 end) as [Healthcare_often],
sum(case when Healthcare ='5' then 1 else 0 end) as [Healthcare_very often]
,avg(Cast(Healthcare as float)) as Average
,count(Healthcare) as N_Healthcare
from Member
where Healthcare > '0')
(select
sum(case when Religious ='1' then 1 else 0 end) as [Religious_never],
sum(case when Religious ='2' then 1 else 0 end) as [Religious_not often],
sum(case when Religious ='3' then 1 else 0 end) as [Religious_average],
sum(case when Religious ='4' then 1 else 0 end) as [Religious_often],
sum(case when Religious ='5' then 1 else 0 end) as [Religious_very often],
Avg(cast(Religious as float)) as Average
,count(Religious) as N_Religious
from Member
where Religious > '0')
(select
sum(case when Sport ='1' then 1 else 0 end) as [Sport_never],
sum(case when Sport ='2' then 1 else 0 end) as [Sport_not often],
sum(case when Sport ='3' then 1 else 0 end) as [Sport_average],
sum(case when Sport ='4' then 1 else 0 end) as [Sport_often],
sum(case when Sport ='5' then 1 else 0 end) as [Sport_very often],
Avg(cast(Sport as float)) as Average
,count(Sport) as N_Sport
from Member
where Sport > '0')
你想吃點什麼列從合併查詢來獲取? – complex857 2012-08-07 20:01:26
你的目標是什麼?你試過什麼了? – gcochard 2012-08-07 20:01:34
我的目標是爲每個列和適當的計數設置一個值。我遇到的問題是在Where聲明中......我將發佈我在下面嘗試的內容。 – Stan 2012-08-07 20:08:07