排序和從其他表

-3

School：

"CREATE TABLE IF NOT EXISTS school (" + 
       "id INTEGER PRIMARY KEY AUTOINCREMENT, " + 
       "name CHAR NOT NULL" + 
       ");"

Teacher：

"CREATE TABLE IF NOT EXISTS teacher (" + 
       "id INTEGER PRIMARY KEY AUTOINCREMENT, " + 
       "school_id NOT NULL, " + 
       "name CHAT NOT NULL, " + 
       "wage REAL NOT NULL," + 
       "CONSTRAINT fk_school_id FOREIGN KEY (school_id) " + 
       "REFERENCES school (id) ON DELETE CASCADE" + 
       ");"

，我需要選擇所有學校通過總量工資排序花費在教師工作人員身上。

例子：教師

id, school_id, name, wage 
1, 1, 'teacher1', 2000 
2, 1, 'teacher2', 1500 
3, 2, 'teacher3', 5600 
4, 3, 'teacher4', 4300 
5, 4, 'teacher5', 5000 
6, 4, 'teacher6', 3500 
7, 4, 'teacher7', 4000

這應該是預期的結果：

school.id, school.name 
4, 'school 4' 
2, 'school 2' 
3, 'school 3' 
1, 'school 1'

來源

2015-09-25 cRobot

那你試試？ –

我試過了，非常接近下面的答案，但我不知道如何通過SUM進行排序。 SELECT school.id，school.name，SUM（teacher.wage）從學校JOIN上teacher.school_id = school.id GROUP BY教師school.id，school.name – cRobot

SQL查詢可以是：

SELECT s.id, s.name, SUM(t.wage) 
FROM school AS s 
JOIN teachers AS t on t.school.id = s.id 
GROUP BY s.id, s.name 
ORDER BY 3 DESC;

來源

2015-09-25 08:44:30 LaurentY

謝謝你的回覆，我'得到這個錯誤：「執行查詢時發生錯誤：接近」3「：語法錯誤」 – cRobot

@ User2077248，我更新了我的答案 – LaurentY

op稱爲薪水工資，您應該通過SUM（t.salary）不是預期產出的一部分 –

排序和從其他表

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