Tweepy Stream error：__init __（）需要剛好3個參數（給出4個參數）

Question

我試圖使用Tweepy python api創建一個twitter搜索流，但我面臨一個錯誤。這是我想執行的代碼，我得到的錯誤 -

from tweepy.streaming import StreamListener 
from tweepy import OAuthHandler 
from tweepy import Stream 

# Twitter Credentials 
access_token_key = "*****" 
access_token_secret = "*****" 
consumer_key = "*****" 
consumer_secret = "*****" 

class StdOutListener(StreamListener): 
    """ A listener handles tweets that are the received from the stream. 
    This is a basic listener that just prints received tweets to stdout. 
    """ 

    def on_data(self, data): 
     print data 
     return True 

    def on_error(self, status): 
     print status 

if __name__ == '__main__': 
    x = StdOutListener() 
    auth = OAuthHandler(consumer_key, consumer_secret) 
    auth.set_access_token(access_token_key, access_token_secret) 

    stream = Stream(auth, x, "microsoft") 
    response = stream.filter(track=['microsoft']) 

print response 

Answer 1

問題出在流intitialization>

File "code.py", line 28, in <module> 
    stream = Stream(auth, x, "microsoft") 
__init__() takes exactly 3 arguments (4 given) 

（感謝您的幫助對不起，我是初學者。）行：

stream = Stream(auth, x, "microsoft") 

，應該是

stream = Stream(auth, x) 

跟蹤的單詞不通過構造函數傳遞，而是通過filter方法傳遞。

Answer 2

Stream()只需要2個參數（加self的綁定方法）：

stream = Stream(auth, x) 
stream.filter(track=['microsoft']) 

見的Tweepy項目給出的streaming example。

應該將307重定向處理爲非錯誤;你可以告訴Tweepy從on_error處理程序返回True繼續：

def on_error(self, status): 
    print status 
    if status == 307: 
     return True