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我是一個嵌入式編程人員,使用多線程應用程序,它將通過串行線接收像素數據並將其顯示在窗口中。我使用openCV的cvSetData()方法來複制通過串行線接收到的數據並將其填充到openCV數組中。還使用cvShowImage()函數,我正在顯示不斷更新的像素數據(顯示視頻的概念)。OpenCV多線程XInitThreads錯誤
這裏是我的代碼片段:
//-------------------------------------Start of code------------------------------------//
#include <stdio.h>
#include <stdlib.h>
#include <fcntl.h>
#include <unistd.h>
#include <termios.h>
#include <sys/select.h>
#include "serial_comm_defines.h"
#include <opencv2/highgui/highgui.hpp>
#include <signal.h>
#include <time.h>
#include <sys/time.h>
#include <pthread.h>
extern unsigned char array[COUNT_LIM];
IplImage *newimage;
img_disp_method(void)
{
cvSetData((CvArr*)newimage, (void*)array, 1556);
cvNamedWindow("Mywindow",CV_WINDOW_FREERATIO);
cvResizeWindow("Mywindow", 1556, 360);
cvShowImage("Mywindow",(CvArr*)newimage);
cvWaitKey(1);
}
void *serial_thread_method(void* my_fd)
{
clock_t start = 0, end = 0;
double time_taken = 0;
if ((int)my_fd<0)
printf("\nError opening device file\n");
else
{
printf("\nDevice file opened successfully\n");
if (serial_config((int)my_fd) < 0)
printf("\nUnable to configure serial port\n");
else
{
printf("\nSerial port configured successfully\n");
for(;;)
{
start = clock();
serial_read((int)my_fd);
end = clock();
printf("\nTime taken:%f seconds\n", (double)((end-start)/CLOCKS_PER_SEC));
}
}
}
close ((int)my_fd);
return NULL;
}
int main(int argc, char **argv)
{
pthread_t serial_read_thread;
int my_fd=0, i=0, temp=0, serial_thread_ret=0;
newimage = cvCreateImageHeader(cvSize(HEIGHT, WIDTH), IPL_DEPTH_8U, 0x01);
struct timeval my_value={0,10000};
struct timeval my_interval={0,10000};
struct itimerval my_timer={my_interval,my_value};
setitimer(ITIMER_REAL, &my_timer, 0);
signal(SIGALRM, img_disp_method);
my_fd = open_device_file((char**)argv);
if ((serial_thread_ret = pthread_create(&serial_read_thread, NULL, serial_thread_method, (void*)my_fd) == 0))
fprintf(stdout, "\nSerial read thread created successfully\n");
else
perror("\nError creating serial read thread\n");
pthread_join(&serial_read_thread, NULL);
cvReleaseImageHeader(&newimage);
return NULL;
}
//----------------------------------------End of code--------------------------------------//
的代碼編譯的罰款。但是當我執行二進制文件時,會引發以下錯誤。我還觀察到,如果將計時器的值(my_value和my_interval的值)更改爲大於30ms(30000)的任何位置,代碼就可以正常工作。請解釋發生了什麼。
請避免的OpenCV的過時C-API。他們已經在2010年轉向了C++,所以你應該。 – berak