讓我請出示的另一個例子...... 我能不能夠在PHP中創建這種觀點(而我可以在phpMyAdmin)請求適用於phpadmin但不是在我的PHP代碼
$sql="CREATE VIEW ratings.rtgemissfitch AS
SELECT derivedtable. ISIN
FROM
(SELECT ISIN, MAX(Date_Notation_Emission) FROM ratings.ratingsemissionfitch as derivedtable GROUP BY ISIN) ";
但我可以在PHP這樣做:
$sql="CREATE VIEW ratings.rtgemissfitch AS
(SELECT ISIN, MAX(Date_Notation_Emission) FROM ratings.ratingsemissionfitch as derivedtable GROUP BY ISIN) ";
我真的不understand..First所有的,對不起,我的英語,我是法國人.. 我真的不明白,爲什麼要求,在phpadmin上運行,不工作在我的php代碼.. probaby派生表... 所以,我希望得到最後的評級惠譽: 在phpMyAdmin的SQL請求,其完美的作品:
SELECT `DBFITCH`.`ISIN`, `RATING_FITCH`as FITCH_RTG
FROM
(SELECT `ISIN`, MAX(`RATING_DATE`) as LastUpdate
FROM `ratings`.`ratingsemissionfitch` GROUP BY ISIN) as LAST
INNER JOIN `ratings`.`ratingsemissionfitch` as DBFITCH
ON
DBFITCH.`ISIN`= LAST.`ISIN`
AND DBFITCH.`RATING_DATE`=LAST.LastUpdate
在PHP中,下面的代碼至極不運行:
$sql="CREATE VIEW ratings.rtgemissfitch AS
SELECT DBFITCH.ISIN, RATING_FITCH as FITCH_RTG
FROM
(SELECT ISIN, MAX(RATING_DATE) as LastUpdate
FROM ratings.ratingsemissionfitch GROUP BY ISIN) as LAST
INNER JOIN ratings.ratingsemissionfitch as DBFITCH
ON
DBFITCH.ISIN= LAST.ISIN
AND DBFITCH.RATING_DATE=LAST.LastUpdate";
$req = $bdd->exec($sql);
讓我請出示的其他例子...
我不能夠在PHP中創建這種觀點(而我可以在phpMyAdmin)
$sql="CREATE VIEW ratings.rtgemissfitch AS
SELECT derivedtable. ISIN
FROM
(SELECT ISIN, MAX(Date_Notation_Emission) FROM ratings.ratingsemissionfitch as derivedtable GROUP BY ISIN) ";
但我可以在PHP這樣做:
$sql="CREATE VIEW ratings.rtgemissfitch AS
(SELECT ISIN, MAX(Date_Notation_Emission) FROM ratings.ratingsemissionfitch as derivedtable GROUP BY ISIN) ";
我真不明白..提前 感謝,
您是否在日誌中發現任何錯誤?可能是因爲這兩個實例中的MySQL用戶不同。 – Daedalus 2013-03-13 15:17:56
1)它們不是同一個查詢。它們甚至不是相同類型的查詢('SELECT' vs'CREATE VIEW')2)它究竟如何失效? – 2013-03-13 15:18:47
在$ bdd類中啓用錯誤報告。沒有其他辦法。 – 2013-03-13 15:19:06