這是解決
只需要改變字符串JSONObject的身體。
Solamente tenia que cambiar el cuerpo String JSONObject。
String url = "http://example.json";
String result;
String tipoConexion = Autenticacion.getConnectionString();
public Consumo4()
{
try{
JSONObject json = new JSONObject (
"{"+
"'name' : 'test',"+
"'email' : '[email protected]',"+
"'password' : 'password',"+
"'gender' : 0,"+
"}"
);
HttpConnection connection = (HttpConnection)Connector.open(url+tipoConexion);
connection.setRequestMethod(HttpConnection.POST);
connection.setRequestProperty("Content-Type", "application/json;charset=UTF-8");
connection.setRequestProperty("Accept", "application/json");
connection.setRequestProperty("Content-Length", Integer.toString(json.length()));
System.out.println("JSON A ENVIAR --> " + json);
String size = "" + json.length();
OutputStream os = connection.openOutputStream();
os.write(json.toString().getBytes("UTF-8"));
ByteArrayOutputStream baos = new ByteArrayOutputStream();
InputStream responseData = connection.openInputStream();
byte[] buffer = new byte[20000];
int bytesRead = responseData.read(buffer);
while(bytesRead > 0) {
baos.write(buffer, 0, bytesRead);
bytesRead = responseData.read(buffer);
}
baos.close();
connection.close();
result = new String(baos.toByteArray(), "UTF-8");
System.out.println("JSON RECIBIDO --> " + result);
} catch (IOException ex) {
//screen.requestFailed(ex.toString());
System.out.println("FALLÓ:: " + ex);
} catch (Exception e) {
e.printStackTrace();
}
}
檢查下面的文章 – alishaik786
爲請求創建一個JSON對象,使用請求的JSON對象的toString()方法返回的數據。 – Rupak