你好,我有使用MySQL PHP形式Netbeans中出現的問題,更新的一個問題是: 「
注意:未定義的變量:fetched_row在C:\ XAMPP \ htdocs目錄\ Resume_DB \ PHP \ Edication_Edit.php上線
「更新MySQL的使用PHP的形式使用文本框數據庫
在我的文本框中的所有4。我的代碼是:
<?php
mysql_connect("localhost", "root", "");
mysql_select_db("cs266db_db1");
if(isset($_GET['edit_id']))
{
$sql_query="SELECT * FROM education Where Edit_Education=".$_GET['edit_id'];
$result_set= mysql_query($sql_query);
$fetched_row= mysql_fetch_array($result_set);
}
if(isset($_POST['btn_update']))
{
//variables for input data
$Class = $_POST['Class'];
$Discipline = $_POST['Discipline'];
$Description = $_POST['Description'];
$Term = $_POST['Term'];
//sql query for update data
$sql_query = "UPDATE Education SET Class='$Class', Discipline='$Discipline', Description='$Description', Term='$Term' WHERE Education_Edit=".$_GET['edit_id'];
//sql query execution function
if(mysql_query($sql_query))
{
?>
<script type='text/javascript'>
alert('Data Has Been Updated');
window.location.href='Eduaction.php';
</script>
<?php
}
else
{
?>
<script type='text/javascript'>
alert('Error Occured while Updating Data');
</script>
<?php
}
//sql query execution function
}
if(isset($_POST['btn-cancel']))
{
header("Location: Education.php");
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Edit Education</title>
</head>
<body>
<center>
<div id="header">
<div id="content">
<label>Edit Education</label>
</div>
</div>
<div id="body">
<div id="content">
<form method="post">
<table align="center">
<tr>
**<td><input type="text" name="Class" placeholder="Class" value="<?php echo $fetched_row['Class']; ?>" required /></td>
</tr>
<tr>
<td><input type="text" name="Discipline" placeholder="Discipline" value="<?php echo $fetched_row['Discipline']; ?>" required /></td>
</tr>
<tr>
<td><input type="text" name="Description" placeholder="Description" value="<?php echo $fetched_row['Description']; ?>" required /></td>
</tr>
<tr>
<td><input type="Text" name="Term" placeholder="Term" value="<?php echo $fetched_row['Term']; ?>" required</td>**
</tr>
<tr>
<td>
<button type="submit" name="btn-update"><strong>UPDATE</strong></button>
<button type="submit" name="btn-cancel"><strong>Cancel</strong></button>
</td>
</tr>
</table>
</form>
</div>
<div id="footer">
<div id="content">
</div>
</div>
</center>
</body>
</html>
有什麼想法?感謝您的幫助球員
'fetched_row'設置在一個條件內,但在'view'沒有條件.. – Rayon
您是否嘗試使用mysql_error()?如果isset($ _ GET ['edit_id'])的條件是** true **,那麼應該是一個mysql錯誤,並且您可以使用mysql_error()語句來檢查它。 – Fabricio
好的,修復了很棒的錯誤!謝謝Greg。但是SQL不會更新。任何想法爲什麼? –