1
下面的登錄系統正常工作。但是,當從Chrome瀏覽器清除cookie時,在用戶首次登錄時不起作用,在cookie被清除後第二次起作用。Cookie清除後,登錄功能無法正常工作
任何想法爲什麼從Chrome中清除cookie後第一次登錄不起作用?
由於提前,
約翰
<?php
if (!isLoggedIn())
{
if (isset($_POST['cmdlogin']))
{
if (checkLogin($_POST['username'], $_POST['password']))
{
show_userbox();
} else
{
echo "Incorrect Login information !";
show_loginform();
}
} else
{
show_loginform();
}
} else
{
show_userbox();
}
?>
登錄表單功能:
function show_loginform($disabled = false)
{
echo '<form name="login-form" id="login-form" method="post" action="./index.php">
<div class="usernameformtext"><label title="Username">Username: </label></div>
<div class="usernameformfield"><input tabindex="1" accesskey="u" name="username" type="text" maxlength="30" id="username" /></div>
<div class="passwordformtext"><label title="Password">Password: </label></div>
<div class="passwordformfield"><input tabindex="2" accesskey="p" name="password" type="password" maxlength="15" id="password" /></div>
<div class="registertext"><a href="http://www...com/.../register.php" title="Register">Register</a></div>
<div class="lostpasswordtext"><a href="http://www...com/.../lostpassword.php" title="Lost Password">Lost password?</a></div>
<p class="loginbutton"><input tabindex="3" accesskey="l" type="submit" name="cmdlogin" value="Login" ';
if ($disabled == true)
{
echo 'disabled="disabled"';
}
echo ' /></p></form>';
}
登錄功能:
function isLoggedIn()
{
if (isset($_SESSION['loginid']) && isset($_SESSION['username']))
{
return true; // the user is loged in
}
else
{
return false; // not logged in
}
return false;
}
function checkLogin($u, $p)
{
global $seed; // global because $seed is declared in the header.php file
if (!valid_username($u) || !valid_password($p) || !user_exists($u))
{
return false; // the name was not valid, or the password, or the username did not exist
}
//Now let us look for the user in the database.
$query = sprintf("
SELECT loginid
FROM login
WHERE
username = '%s' AND password = '%s'
AND disabled = 0 AND activated = 1
LIMIT 1;", mysql_real_escape_string($u), mysql_real_escape_string(sha1($p . $seed)));
$result = mysql_query($query);
// If the database returns a 0 as result we know the login information is incorrect.
// If the database returns a 1 as result we know the login was correct and we proceed.
// If the database returns a result > 1 there are multple users
// with the same username and password, so the login will fail.
if (mysql_num_rows($result) != 1)
{
return false;
} else
{
// Login was successfull
$row = mysql_fetch_array($result);
// Save the user ID for use later
$_SESSION['loginid'] = $row['loginid'];
// Save the username for use later
$_SESSION['username'] = $u;
// Now we show the userbox
return true;
}
return false;
}
同樣的問題在這裏! (與Firefox) - 你現在找到了解決方案嗎? – stoefln 2012-04-12 10:24:43