SQL中存在的問題具有子句

Question

當我嘗試執行下面的sql時，收到一條錯誤消息，指出無效的列名距離。我沒有在我的sql中發佈過那麼多，所以我不確定這個isue是什麼。先謝謝您的幫助！

SELECT ID, 
    3959 * ACOS(COS(RADIANS(34.743305)) 
    * COS(RADIANS(Lattitude)) * COS(RADIANS(Longitude) - RADIANS(- 85.059586)) 
    + SIN(RADIANS(34.743305)) * SIN(RADIANS(Lattitude))) AS distance 
FROM RetailerRegistration 
HAVING (distance < 25) 

Answer 1

having與group by一起使用。我認爲你有它與where ...混淆...此外，請嘗試將公式放入where子句中，而不是引用別名。

SELECT ID, 
    3959 * ACOS(COS(RADIANS(34.743305)) 
    * COS(RADIANS(Lattitude)) * COS(RADIANS(Longitude) - RADIANS(- 85.059586)) 
    + SIN(RADIANS(34.743305)) * SIN(RADIANS(Lattitude))) AS distance 
FROM RetailerRegistration 
WHERE 
    3959 * ACOS(COS(RADIANS(34.743305))  
    * COS(RADIANS(Lattitude)) * COS(RADIANS(Longitude) - RADIANS(- 85.059586))  
    + SIN(RADIANS(34.743305)) * SIN(RADIANS(Lattitude))) < 25 

Answer 2

你不使用任何一組由..trying做這樣的：

SELECT ID, 3959 * ACOS(COS(RADIANS(34.743305)) * COS(RADIANS(Lattitude)) * COS(RADIANS(Longitude) - RADIANS(- 85.059586)) + SIN(RADIANS(34.743305)) * SIN(RADIANS(Lattitude))) AS distance FROM RetailerRegistration where (distance < 25) 

HAVING子句來強加行不是個別行

希望這有助於集團condidtion。 ...

Answer 3

的問題是，你正試圖引用您在SELECT列表中創建一個別名，我建議使用子查詢，然後使用您的別名：

select ID, distance 
from 
(
    SELECT ID, 
    3959 * ACOS(COS(RADIANS(34.743305)) 
     * COS(RADIANS(Lattitude)) * COS(RADIANS(Longitude) - RADIANS(- 85.059586)) 
     + SIN(RADIANS(34.743305)) * SIN(RADIANS(Lattitude))) AS distance 
    FROM RetailerRegistration 
) d 
where distance < 25; 

的邏輯順序處理查詢是：

1. FROM
2. WHERE
3. GROUP BY
4. HAVING
5. 選擇
6. ORDER BY

結果別名distance尚未被定義爲您的WHERE子句。解決這個問題的一種方法是使用子查詢。