對此的最佳查詢是什麼？

Question

我有表總線，街道，route_going，route_return

在表中的街道我有

實施例：

id | name 
1 | street1 
2 | street2 
3 | street4 
... 
n | streetn 

表route_going，我有實施例：

id_bus | id_street | order 
101 | 1   | 1 
101 | 2   | 2 
101 | 5   | 3 

... 

表route_return，我有例子：

id_bus | id_street | order 
101 | 3   | 1 
101 | 2   | 2 
101 | 1   | 3 

... 

好的，在這個例子中，公交車101依次從街道1,2和5行駛。並按照此順序從大街3,2和1返回。

我想知道哪些公交車在街道通過 'X' 和街道 'Y'（第一個X，後來Y）

例如：

x = 1, y = 5 -> the bus 101 pass 
x = 1, y = 3 -> the bus 101 pass 
x = 3, y = 1 -> the bus 101 pass 
x = 3, y = 5 -> the bus 101 don't pass 

所以，我的SQL的查詢公交車是...（通過爲街道1和5舉例）

select * from bus as b where 
-- The bus passes between the 2 streets at the going route?? 
exists (select * from route_going as rg1, route_going as rg2,street as r1,street as r2 where rg1.id_bus = rg2.id_bus and rg1.id_street = r1.id and rg2.id_street = r2.id and r1.id = 1 and r2.id = 5 and b.bus_id = rg1.id_bus and rg1.order <= rg2.order) 
-- The bus passes between the 2 streets at the return route?? 
or exists (select * from route_return as rg1, route_return as rg2,street as r1,street as r2 where rg1.id_bus = rg2.id_bus and rg1.id_street = r1.id and rg2.id_street = r2.id and r1.id = 1 and r2.id = 5 and b.bus_id = rg1.id_bus and rg1.order <= rg2.order) 
-- The bus passes between the 2 streets at the going route first and return route later?? 
or exists (select * from route_going as rg1, route_return as rg2,street as r1,street as r2 where rg1.id_bus = rg2.id_bus and rg1.id_street = r1.id and rg2.id_street = r2.id and r1.id = 1 and r2.id = 5 and b.bus_id = rg1.id_bus) 

所以，我覺得這個查詢是不好的。有人可以幫我說出這個搜索的「最佳」查詢嗎？

Answer 1

SET @x = 1; 
SET @y = 5; 

SELECT x.id_bus 
    FROM 
    (SELECT *,0 returning FROM route_going UNION SELECT *, 1 FROM route_return) x 
    JOIN 
    (SELECT *,0 returning FROM route_going UNION SELECT *, 1 FROM route_return) y 
    ON y.id_bus = x.id_bus 
    AND (y.returning > x.returning OR (y.returning = x.returning AND y.porder > x.porder)) 
WHERE x.id_street = @x 
    AND y.id_street = @y; 

Answer 2

select 
street.name, 
route_going.id_bus,route_going.id_street 
route_return.id_bus,route_return.id_street 
on street.id=route_going.id_street and 
route_return.id_street=route_going.id_street; 

試試這個。謝謝