如何在單獨的實體中將多個列從一個實體連接到單個列？

Question

我正在嘗試爲減肥門診的客戶做一頓飯調度數據庫。這些都是一些食譜：

+-----------+-----------------------+ 
| recipe_ID | recipe_name   | 
+-----------+-----------------------+ 
|   1 | Healthy Burritos  | 
|   2 | Stuffed Peppers  | 
|   3 | Breakfast Pizza Slice | 
+-----------+-----------------------+ 

這是一天一個計劃：

+--------+-----------+-------+--------+ 
| ddp_ID | breakfast | lunch | dinner | 
+--------+-----------+-------+--------+ 
|  1 |   3 |  1 |  2 | 
+--------+-----------+-------+--------+ 

在計劃在早餐，午餐和晚餐每個號碼爲外鍵指的是配方的ID。我想執行一個查詢，獲取每個配方的名稱以顯示給用戶。這是我得到了什麼，但我發現了以下錯誤，我似乎無法來解決：ERROR 1066（42000）：不是唯一的表/別名：「daily_diet_plan」

SELECT 
recipe.recipe_name 
FROM 
recipe 
INNER JOIN daily_diet_plan ON (daily_diet_plan.breakfast = recipe.recipe_ID) 
INNER JOIN daily_diet_plan ON (daily_diet_plan.lunch = recipe.recipe_ID) 
INNER JOIN daily_diet_plan ON (daily_diet_plan.dinner = recipe.recipe_ID); 

謝謝這麼多的任何幫助，你可以提供！對此，我真的非常感激。

編輯：這工程！

SELECT recipe.recipe_name 
FROM recipe 
LEFT JOIN daily_diet_plan as brkfast ON (brkfast.breakfast = recipe.recipe_ID) 
LEFT JOIN daily_diet_plan as lunch ON (lunch.lunch = recipe.recipe_ID) 
LEFT JOIN daily_diet_plan as dinner ON (dinner.dinner = recipe.recipe_ID) order by recipe.recipe_name; 

Answer 1

更新查詢（我已經加入DIFF別名：

SELECT 
recipe.recipe_name 
FROM 
recipe 
INNER JOIN daily_diet_plan as brkfast ON (brkfast.breakfast = recipe.recipe_ID) 
INNER JOIN daily_diet_plan as lunch ON (lunch.lunch = recipe.recipe_ID) 
INNER JOIN daily_diet_plan as dinner ON (dinner.dinner = recipe.recipe_ID);