我試圖得到一個查詢來總結每週員工的工作。例如,John Doe本週總共有12張門票,其中4張是休息/修復,4張是增強型,另外4張是未分類的。SQLite計數摘要查詢
這是我到目前爲止有:
SELECT (users.first_name || ' ' || users.last_name) AS Name,
COUNT(tickets.id) AS 'Number of Tickets Closed',
COUNT(tickets.category = 'Maintenance') AS 'Maintenance Tickets',
COUNT(tickets.category = 'After Hours') AS 'After Hours Tickets',
COUNT(tickets.category = 'Break Fix') AS 'Break Fix Tickets',
COUNT(tickets.category = 'Enhancement') AS 'Enhancement Tickets',
COUNT(tickets.category = '') AS 'Non Categorized Tickets'
FROM tickets, users
ON tickets.assigned_to=users.id
WHERE (tickets.status = 'closed') AND
(tickets.closed_at >= '2011-07-16 00:00:00') AND
(tickets.closed_at <= '2011-07-22 23:59:59')
GROUP BY Name;
下面是一個簡單的結果:
約翰DOE1 10 10 10 10 10 10
約翰DOE2 2 2 2 2 2 2
John Doe3 25 24 24 24 24 24
John Doe4 2 2 2 2 2 2
約翰Doe5 12 10 10 10 10 10
約翰Doe6 7 7 7 7 7 7
此查詢確實如我預料到的所有列具有相同的總不太工作(關閉的票總數,以下列似乎只包含分類的。)幫助?
編輯
只是想後的功能代碼:
SELECT (users.first_name || ' ' || users.last_name) AS Name,
COUNT(tickets.id) AS 'Number of Tickets Closed',
COUNT(case tickets.category when 'Maintenance' then 1 else null end) AS 'Maintenance Tickets',
COUNT(case tickets.category when 'After Hours' then 1 else null end) AS 'After Hours Tickets',
COUNT(case tickets.category when 'Break Fix' then 1 else null end) AS 'Break Fix Tickets',
COUNT(case tickets.category when 'Enhancement' then 1 else null end) AS 'Enhancement Tickets',
COUNT(case tickets.category when '' then 1 else null end) AS 'Non Categorized Tickets'
FROM tickets, users
ON tickets.assigned_to=users.id
WHERE (tickets.status = 'closed') AND
(tickets.closed_at >= '2011-07-16') AND
(tickets.closed_at <= '2011-07-22')
GROUP BY Name;
這工作!非常感謝! – Bigun