總結兩個總結語句

DECLARE @aracct VARCHAR(12) 
    SET @aracct = '49920813' 
DECLARE @item_no VARCHAR(12) 
    SET @item_no = '2319' 
SELECT tran_id, * FROM transactions 
    WHERE account = @aracct AND item_no = @item_no 
/*-----------Use if removing certain items from a check-----------*/ 
CREATE TABLE itemtable (items VARCHAR(6), account VARCHAR(12)) 
    INSERT INTO itemtable VALUES ('2299', @aracct) 
    INSERT INTO itemtable VALUES ('2300', @aracct) 
    --INSERT INTO @itemtable VALUES ('') 
DECLARE @tran_id_pmt VARCHAR(6) 
    SET @tran_id_pmt = '209413' 

SELECT I1.result - I2.result AS 'final result' 
FROM (SELECT SUM(amt_paid) AS result 
     FROM transactions 
     WHERE account = @aracct AND item_no = @item_no) AS I1 
JOIN (SELECT SUM(amt_paid) AS result 
     FROM transactions 
     WHERE account = @aracct AND item_no = (SELECT items FROM itemtable)) AS I2 
    ON (I1.account = I2.account)

試圖獲得總和2選擇語句，然後總結這2個語句，但我不斷收到錯誤。有任何想法嗎？總結兩個總結語句

來源

2016-03-15 Femmer

你得到了什麼錯誤？ \t請閱讀[**如何提問**]（http://stackoverflow.com/help/how-to-ask） \t \t這裏是[** START **]（ http://spaghettidba.com/2015/04/24/how-to-post-at-sql-question-on-a-public-forum/）瞭解如何提高您的問題質量並獲得更好的答案。 –

那麼現在它是說I1.account不是一個正確的列名稱...我試着做transactions.account = itemtable.account，但它告訴我，它不能綁定 – Femmer

你到底在哪裏得到那個錯誤？在選擇？你的數據庫模式是什麼？ –

您需要包括account你的子查詢，所以你可以在ON條件

SELECT I1.result - I2.result AS 'final result' 
FROM (SELECT account, SUM(amt_paid) AS result 
      ^^^^^^^ 
     FROM transactions 
     WHERE account = @aracct AND item_no = @item_no 
     GROUP BY account) AS I1 
     ^^^^^^^^^^^^^^^^ 
JOIN (SELECT account, SUM(amt_paid) AS result 
     FROM transactions 
     WHERE account = @aracct AND item_no = (SELECT items FROM itemtable) 
     GROUP BY account) AS I2 
    ON (I1.account = I2.account) 
     ^^^^^^^^

使用它，你也可以用一個有條件的聚合解決它。

SELECT SUM(CASE WHEN item_no = @item_no THEN amt_paid 
             ELSE 0 
      END) 
     - 
     SUM(CASE WHEN item_no IN (SELECT items FROM itemtable) THEN amt_paid 
                   ELSE 0 
      END) AS 'final result'   
FROM Transactions 
WHERE account = @aracct

來源

2016-03-15 15:06:01

仍然是同樣的錯誤。（I1.account = I2.account）列名無效 – Femmer

沒有意義。再次檢查是否有錯別字。嘗試先運行內部選擇，然後檢查列名。 –

隨着你給我的第二選擇，它告訴我消息130，級別15，狀態1，行19 無法對包含聚合或子查詢的表達式執行聚合函數。 – Femmer

總結兩個總結語句

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