SELECT sum(l.interestrt*d.bidspotrate) AS [Interest Rate in MYR],
SUM (l.interestsprd * d.bidspotrate), sum(l.penaltyrt*d.bidspotrate)
FROM loan l,
danadb d
如何總結上面的所有sql語句?我不知道如何總結不同的列。 謝謝。如何總結sql語句
SELECT sum(l.interestrt*d.bidspotrate) AS [Interest Rate in MYR],
SUM (l.interestsprd * d.bidspotrate), sum(l.penaltyrt*d.bidspotrate)
FROM loan l,
danadb d
如何總結上面的所有sql語句?我不知道如何總結不同的列。 謝謝。如何總結sql語句
這是怎麼回事?
SELECT SUM (L.INTERESTRT * D.BIDSPOTRATE) AS "Interest Rate in MYR",
SUM (L.INTERESTSPRD * D.BIDSPOTRATE),
SUM (L.PENALTYRT * D.BIDSPOTRATE)
FROM LOAN L CROSS JOIN DANADB D
謝謝你回答:),但是你剛剛給出的查詢與我的結果一樣。 – mir
@Mir試試這個
(select sum(l.interestrt*d.bidspotrate) as 'Val1',
SUM (l.interestsprd * d.bidspotrate) as 'Val2',
sum(l.penaltyrt*d.bidspotrate) as 'Val3' ,
(SUM(Val1) + SUM(Val2) + SUM(Val3)) as 'Total'
from loan l inner join danadb d on l.someid = d.someid
謝謝你回答:),但是在運行你的查詢的時候出現了錯誤,在第4行說val1,val2和val3的列名無效。 – mir
你可以試試這個,它會給你你所期望的輸出:
select (one+two+three) as [Interest Rate in MYR] from
(select sum(l.interestrt*d.bidspotrate) as [one]
SUM (l.interestsprd * d.bidspotrate) as [two],
sum(l.penaltyrt*d.bidspotrate) as [three]
from loan l,danadb d) t
OR
select (sum(l.interestrt*d.bidspotrate)+
SUM (l.interestsprd * d.bidspotrate)+
sum(l.penaltyrt*d.bidspotrate)) as [Interest Rate in MYR]
from loan l,danadb d
注意:你可以擺脫這些老式的加入和我從表格中共用一列來填充:
FROM loan l
INNER JOIN danadb d ON d.<id> = l.<id>
也許只是添加它們?
SELECT SUM (L.INTERESTRT * D.BIDSPOTRATE)
+ SUM (L.INTERESTSPRD * D.BIDSPOTRATE)
+ SUM (L.PENALTYRT * D.BIDSPOTRATE)
AS "Interest Rate in MYR"
FROM LOAN L CROSS JOIN DANADB D
哦,是的,我根本沒有考慮它。該查詢產生我想要的結果。再次感謝你 :) – mir
在這個問題上你可以找到十幾種在線解決方案。 – Susang
你有沒有想過簡單地添加值? – aaaaaa123456789
'+'一個魔術師這麼做:-) –