重新定位選定表格的標識值

Question

如何根據最後一次計數選擇種類。我已經寫了一個查詢以根據最後一次計數重新排序。但是，如何一次執行10個表格。

declare @last int 
select @last=max(empid) from Table_1 
DBCC CHECKIDENT (Table_1, RESEED, @last) 

，但如何爲超過10桌以上的桌......一氣呵成立足於過去數補種

Answer 1

迭代通過所需的表格做的，然後運行每桌上面的命令。

您必須動態構建SQL語句。

例如，對於SQL Server 2008 R2的（你沒有指定你使用的是什麼），這會做的伎倆：

DECLARE @tname SYSNAME, -- Will hold each table name 
    @sname SYSNAME,  -- Will hold each table's schema name 
    @idcol SYSNAME,  -- Will hold the name of identity column of each table 
    @sql NVARCHAR(4000) -- To build each dynamic SQL statement 

-- Declare a cursor to iterate through all table and schema names 
-- of current database. 
-- Add a WHERE clause here if needed. 
DECLARE idtables CURSOR FOR 
    SELECT name, SCHEMA_NAME(schema_id) 
     FROM sys.tables 

OPEN idtables 

-- Fetch first table and schema name into the corresponding variables 
FETCH NEXT FROM idtables INTO @tname, @sname 
WHILE @@FETCH_STATUS = 0 
BEGIN 
    -- Ensure no dirty values if table has no identity column 
    SET @idcol = NULL 
    -- Build 1st statement. 
    -- Objective: get identity column name, if any. 
    SET @sql = 'SELECT @idcolname = name 
     FROM sys.columns 
     WHERE object_id = OBJECT_ID(''' + @sname + '.' + @tname + ''') 
      AND is_identity = 1' 
    -- Run the statement and store the result into @idcol 
    EXEC sp_executesql @sql, 
         N'@idcolname sysname OUTPUT', 
         @idcolname = @idcol OUTPUT 
    IF @idcol IS NOT NULL 
    BEGIN 
     -- Time for the 2nd statement. 
     -- Objective: find the maximum identity value and reseed the table. 
     SET @sql = 'DECLARE @lastid int; 
      SELECT @lastid = MAX(' + @idcol + ') 
       FROM [' + @sname + '].[' + @tname + ']; 
      IF @lastid IS NOT NULL 
       DBCC CHECKIDENT (''' + @sname + '.' + @tname + ''', RESEED, @lastid)' 
     EXEC SP_EXECUTESQL @sql 
    END 
    FETCH NEXT FROM idtables INTO @tname, @sname 
END 

CLOSE idtables 
DEALLOCATE idtables 

Answer 2

你不需要選擇@最後= MAX（EMPID ）Table_1

DBCC CHECKIDENT（Table_1，RESEED）將得到最後一個id（如果empid是標識列）。

此代碼將補種所有表：

SET NOCOUNT ON 
DECLARE @lcl_name VARCHAR(100) 
DECLARE cur_name CURSOR FOR 

SELECT TABLE_NAME 
FROM information_schema.tables 
WHERE TABLE_TYPE = 'BASE TABLE' 

OPEN cur_name 
FETCH NEXT FROM cur_name INTO @lcl_name 
WHILE @@Fetch_status = 0 
BEGIN 

DBCC CHECKIDENT (@lcl_name, RESEED); 

PRINT @lcl_name 
FETCH NEXT FROM cur_name INTO @lcl_name 
END 
CLOSE cur_name 
DEALLOCATE cur_name 
SET NOCOUNT OFF 

Answer 3

感謝這讓我擺脫困境的一個偉大的答案。這裏是我的更全面的版本

DECLARE @idcol nvarchar(max) 
DECLARE @sql nvarchar(max) 
DECLARE @sname nvarchar(max) 
DECLARE @tname nvarchar(max) 

DECLARE idtables CURSOR FOR 
SELECT t.name, s.name 
FROM sys.columns C 
    INNER JOIN sys.tables T ON C.object_id = T.object_id 
    INNER JOIN sys.schemas s ON S.schema_id = T.schema_id 
WHERE is_identity = 1; 

OPEN idtables 

-- Fetch first table and schema name into the corresponding variables 
FETCH NEXT FROM idtables INTO @tname, @sname 
WHILE @@FETCH_STATUS = 0 
BEGIN 
    -- Ensure no dirty values if table has no identity column 
    SET @idcol = NULL 
    -- Build 1st statement. 
    -- Objective: get identity column name, if any. 
    SET @sql = 'SELECT @idcolname = name 
     FROM sys.columns 
     WHERE object_id = OBJECT_ID(''' + @sname + '.' + @tname + ''') 
      AND is_identity = 1' 
    -- Run the statement and store the result into @idcol 
    EXEC sp_executesql @sql, 
         N'@idcolname sysname OUTPUT', 
         @idcolname = @idcol OUTPUT 
    IF @idcol IS NOT NULL 
    BEGIN 
     -- Time for the 2nd statement. 
     -- Objective: find the maximum identity value and reseed the table. 
     SET @sql = 'DECLARE @lastid int; 
      SELECT @lastid = MAX(' + @idcol + ') 
       FROM [' + @sname + '].[' + @tname + ']; 
      IF @lastid IS NOT NULL 
       DBCC CHECKIDENT (''' + @sname + '.' + @tname + ''', RESEED, @lastid)' 
     EXEC SP_EXECUTESQL @sql 
    END 
    FETCH NEXT FROM idtables INTO @tname, @sname 
END 

CLOSE idtables 
DEALLOCATE idtables