如何在python中退出while循環？

Question

我正在處理這個簡單的任務，我需要使用2 while while循環。第一個while循環檢查小時數是否小於0，如果是循環，則應繼續詢問用戶。 這裏是我的代碼：

hours = float(input('Enter the hours worked this week: ')) 

count = 0 
while (0 > hours): 
    print ('Enter the hours worked this week: ') 
    count = count + 1 

pay = float(input('Enter the hourly pay rate: ')) 
while (0 > pay): 
    print ('Enter the hourly pay rate: ') 
    count = count + 1 

total_pay = hours * pay 

print('Total pay: $', format(total_pay, ',.2f')) 

Answer 1

您退出循環。

在你的情況，你把用戶的輸入，如果hours < 0，您打印的提示和更新計數，但你不更新小時。

while (0 > hours): 
    print ('Enter the hours worked this week: ') 
    count = count + 1 

應該是：

while (0 > hours): 
    hours = float(input('Enter the hours worked this week: ')) 
    count = count + 1 

同樣薪酬：

while (0 > pay): 
    pay = float(input('Enter the hourly pay rate: ')) 
    count = count + 1 

Answer 2

break是你在找什麼。

x = 100 
while(True): 
    if x <= 0: 
     break 
    x -= 1 
print x # => 0 

至於你的例子，沒有什麼會導致休息的發生。例如：

hours = float(input('Enter the hours worked this week: ')) 

count = 0 

while (0 > hours): 
    print ('Enter the hours worked this week: ') 
    count = count + 1 

您根本沒有編輯hours變量。這隻會繼續打印出"Enter the hours worked this week: "並且無限增加count。我們需要知道提供更多幫助的目標是什麼。

Answer 3

好了，對方的回答顯示瞭如何跳出while循環的，但你也不能分配給工資和小時變量。您可以使用內置的輸入功能讓用戶通過使用兩種或break使病情提供假到什麼到你的程序

hours = float(input('Enter the hours worked this week: ')) 

count = 0 
while (0 > hours): 
    hours = input('Enter the hours worked this week: ') 
    count = count + 1 

pay = float(input('Enter the hourly pay rate: ')) 
while (0 > pay): 
    pay = input('Enter the hourly pay rate: ') 
    count = count + 1 

total_pay = hours * pay 

print('Total pay: $', format(total_pay, ',.2f'))