我想顯示一個整數在一個數組中發生了多少次,但我得到一個無限循環/邏輯錯誤。例如,如果用戶輸入:2,5,6,5,4,3,23,43,2,0,那麼它應該顯示:計數數組參考輸入和顯示計數 - 無限循環
2 occurs 2 times
3 occurs 1 time
4 occurs 1 time
5 occurs 2 times
6 occurs 1 time
23 occurs 1 time
43 occurs 1 time
任何幫助將真正理解。 注意:這不是一個任務或作業,這是一個從Y.D的Java書籍的介紹開始的練習題。郎
import java.util.*;
public class CountNumbers {
public static void main(String[] args) {
System.out.println("Enter the integers between 1 and 100: ");
int[] arrayRefVar = createList();
int[] countNum = countNumbers(arrayRefVar);
displayCount(countNum, arrayRefVar);
}
public static int[] createList() {
Scanner Input = new Scanner(System.in);
int[] List = new int[100];
int i = 0;
while (List[i] != 0) {
List[i] = Input.nextInt();
i++;
}
return List;
}
public static int[] countNumbers(int[] List) {
int[] count = new int[100];
for (int i = 0; i < count.length; i++) {
count[i] = i;
}
int[] countNum = new int[List.length];
for (int i = 0; i < countNum.length; i++) {
countNum[i] = 0;
}
for (int i = 0; i < List.length; i++) {
for (int j = 0; j < count.length; j++) {
if (List[i] == count[j]) {
countNum[i]++;
}
}
}
return countNum;
}
public static void displayCount(int[] countList, int[] arrayRefVar) {
for (int i = 0; i < arrayRefVar.length; i++) {
System.out.println(arrayRefVar[i] + " occurs " + countList[i] + " " + checkPlural(arrayRefVar[i]));
}
}
public static String checkPlural(int n) {
if (n > 1) {
return "times";
} else {
return "time";
}
}
}
如果你要導入的java.util。*,你可能會避免使用'List'作爲變量。這不會很好。 – 2015-02-11 21:51:50