使用xpath選擇特定的xnode

<segmentFlightRef> 
    <referencingDetail> 
     <refQualifier>S</refQualifier> 
     <refNumber>4</refNumber> 
    </referencingDetail> 
    <referencingDetail> 
     <refQualifier>S</refQualifier> 
     <refNumber>1</refNumber> 
    </referencingDetail> 
</segmentFlightRef> 
<segmentFlightRef> 
    <referencingDetail> 
     <refQualifier>S</refQualifier> 
     <refNumber>5</refNumber> 
    </referencingDetail> 
    <referencingDetail> 
     <refQualifier>S</refQualifier> 
     <refNumber>1</refNumber> 
    </referencingDetail> 
</segmentFlightRef> 
    <segmentFlightRef> 
    <referencingDetail> 
     <refQualifier>S</refQualifier> 
     <refNumber>1</refNumber> 
    </referencingDetail> 
    <referencingDetail> 
     <refQualifier>S</refQualifier> 
     <refNumber>5</refNumber> 
    </referencingDetail> 
</segmentFlightRef>

在上面的xml我想要「segmentFlightRef」標記的子節點「refNumber」具有值「5」和「1」。和順序必須考慮，所以我需要它的子節點值5和1 sequencially 請幫我感謝事先只在一個節點使用xpath選擇特定的xnode

來源

2014-02-21 Brijesh Gandhi

的XPath：

//segmentFlightRef[referencingDetail[following-sibling::referencingDetail/refNumber = 1]/refNumber = 5]

來源

2014-02-21 10:43:51 dirkk

thanx爲您的答案，但我編輯了我的問題。我只需要單個節點。請再次參考 –

@BrijeshGandhi更新了我的答案。 – dirkk

非常感謝您 –

的XPath：

//segmentFlightRef[./referencingDetail[./refNumber[text()="5"] and ./following-sibling::referencingDetail[./refNumber[text()="1"]]]]

說明：

//segmentFlightRef[./referencingDetail[...]]

選擇<segmentFlightRef>爲元素的子元素<referencingDetail>與標準如下：

標準我：

./refNumber[text()="5"]

有子元素<refNumber>與內部文本等於"5"。

標準II：

and ./following-sibling::referencingDetail[./refNumber[text()="1"]]

，並與標準的下一個/同級節點<referencingDetail>：具有內部文本子元素<refNumber>等於"1"。

來源

2014-02-21 11:16:23 har07

對於您的代碼段，有些事情是不必要的和/或令人困惑的。因爲您已經在正確的上下文中，因此不需要點構造'。/'。另外，你不必使用'text（）'，因爲它會被自動霧化（並且'text（）'可以顯着減慢你的代碼的速度） – dirkk

使用xpath選擇特定的xnode

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